php - 数组到字符串转换 "Array"存储到数据库

Question

我必须动态地获取用户的输入并将其插入数据库。但是，当我从 PHP 执行查询时，它会在列中插入“Array”。

 <?php
include 'connect.php';

if (isset($_POST['submitCity'])) 
{
$name = $_POST['state'];
$select = "SELECT state_name FROM state WHERE state_name = ?";
$selectstmt = mysqli_stmt_init($conn);
if (!mysqli_stmt_prepare($selectstmt, $select)) 
{
    echo "SQL ERROR OCCURED";
}
else
{
    mysqli_stmt_bind_param($selectstmt, "s", $name);
    mysqli_stmt_execute($selectstmt);
    $result = mysqli_stmt_get_result($selectstmt);
    $row = mysqli_fetch_assoc($result);
}


$cityname = mysqli_real_escape_string($conn,$_POST['city']);
$sql = "INSERT INTO city (state_name, city_name) VALUES (?,?);";
$stmt = mysqli_stmt_init($conn);
if (!mysqli_stmt_prepare($stmt, $sql)) 
{
    echo "SQL ERROR OCCURED";
}
else
{
    mysqli_stmt_bind_param($stmt, "ss", $row ,$cityname);
    mysqli_stmt_execute($stmt);
}
}

?>

Answer 1

当你运行时...

mysqli_stmt_bind_param($stmt, "ss", $row ,$cityname);

$row 检索于...

$row = mysqli_fetch_assoc($result);

和mysqli_fetch_assoc()返回结果集中的字段数组。因此，对于第二次绑定(bind)中的第一个值，您需要获取之后结果集中的值的列...

mysqli_stmt_bind_param($stmt, "ss", $row['state_name'] ,$cityname);

唯一的事情是选择是按 state_name 选择的，所以不确定这与...有何不同

mysqli_stmt_bind_param($stmt, "ss", $name ,$cityname);