mysql - SQL 计算前 6 个值

Question

我尝试创建一个 SQL 查询来计算前 6 个选择中 [Over]='Y' 的次数，但在合并查询中收到错误。

查询获取前 6 名:

 SELECT TOP 6 [Number]
  ,[Over]
  ,[Goal]
 FROM [Test_Hermes].[dbo].[Test]
 ORDER BY Number desc

查询计数:

SELECT COUNT([Over]) 
FROM [dbo].[Test] 
WHERE [OVER] = 'Y';

合并两个查询:

SELECT COUNT([Over]) 
FROM (SELECT TOP 6 [Number]
  ,[Over]
  ,[Goal]
FROM [Test_Hermes].[dbo].[Test]
ORDER BY Number desc) 
WHERE [OVER] = 'Y';

任何帮助将不胜感激! 谢谢

Answer 1

请显示此示例。

 SELECT
   [Number]
  ,[Over]
  ,[Goal]
  , SUM( If(OVER= 'Y',1,0)) AS CNT
 FROM [Test_Hermes].[dbo].[Test]
 ORDER BY Number desc
LIMIT 1,6;