我正在尝试从 MySQL 查询创建多维数组。该阵列有 3 层深。每个用户都有一个membershipid，该成员(member)id可以有多个characterid。每个 characterid 都可以有多个属性。
membershipid -> characterid (can be up tot 3) -> light, racehash.
$query = "SELECT p.membershipid, p.displayname, c.characterid, c.light, c.racehash
FROM Players as p
LEFT JOIN Characters as c
ON c.membershipid = p.membershipid";
$result = $mysqli->query($query) or die("SQL Error: Members konden niet worden opgehaald.");
// Loop through the requested data, add to an array
while ($data = mysqli_fetch_assoc($result)) {
$categorylist[ $data['membershipid'] ] = array(
'displayname' => $data['displayname'],
array('characterid' => $data['characterid'],
'light' => $data['light'],
'racehash' => $data['racehash']
)
);
} // end while statement
// A test to see how many items in array
echo "<pre>\n";
print_r($categorylist);
echo "</pre>\n";
此方法有效，但仅显示每个人的 1 个字符，而查询结果显示每个成员(member) ID 的每个字符 ID。
Array
(
[4611686018428931875] => Array
(
[displayname] => White_Anomaly
[0] => Array
(
[characterid] => 2305843009264668680
[light] => 554
[racehash] => 3887404748
)
)
[4611686018437972738] => Array
(
[displayname] => Bpunisher7
[0] => Array
(
[characterid] => 2305843009277456739
[light] => 392
[racehash] => 2803282938
)
)
SQL 查询的结果如下:
我的数组定义可能有问题，并且每次都会覆盖我的字符 ID，因为我只显示最新的 characterid。
首选数组:
Array
(
[4611686018428931875] => Array
(
[displayname] => White_Anomaly
[characters] => Array
(
[0] => Array
(
[characterid] => 2305843009264668678
[light] => 370
[racehash] => 3887404748
)
[1] => Array
(
[characterid] => 2305843009264668680
[light] => 554
[racehash] => 3887404748
)
)
)
[4611686018437972738] => Array
(
[displayname] => Bpunisher7
[characters] => Array
(
[0] => Array
(
[characterid] => 2305843009265241161
[light] => 534
[racehash] => 2803282938
)
[1] => Array
(
[characterid] => 2305843009265241163
[light] => 524
[racehash] => 3887404748
)
[2] => Array
(
[characterid] => 2305843009277456739
[light] => 392
[racehash] => 3887404748
)
)
)
)
最佳答案
如果您允许我稍微重组您的结果数组，这应该是一个更好的方法:
// Loop through the requested data, add to an array
while ($data = mysqli_fetch_assoc($result)) {
extract($data,EXTR_PREFIX_ALL,'data');
$categorylist[$data_membershipid]['displayname'] = $data_displayname;
$categorylist[$data_membershipid][$data_characterid] = ['light' => $data_light,
'racehash' => $data_racehash];
} // end while statement
如您所见，我已将“characterid”移动为子数组的键。这样做是为了避免覆盖另一个字符。
我还使用了较新的数组表示法。 extract() 只是为了使代码更容易阅读，但您可以删除它。
也许最好将字符放入自己的数组中，如下所示:
// Loop through the requested data, add to an array
while ($data = mysqli_fetch_assoc($result)) {
extract($data,EXTR_PREFIX_ALL,'data');
$categorylist[$data_membershipid]['displayname'] = $data_displayname;
$categorylist[$data_membershipid]['characters'][$data_characterid] = ['light' => $data_light,
'racehash' => $data_racehash];
} // end while statement
关于php - 从 MySQL 查询构建多维 PHP 数组，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/52624893/