我从我的sequelize函数中得到一个JSON
。我必须修改它,因为我必须将其发送给数据库导入程序,数据库导入程序需要固定的形式。
有没有办法自定义此函数以便我得到所需的结果?
型号:
User.associate = function (models) {
User.hasMany(models.SurveyResult)
}`
SurveyResult.associate = function (models) {
SurveyResult.belongsTo(models.User)
功能:
async mediImport (req, res) {
try {
const transaction = await User.findAll({
where: { released: true },
// Select forename as Vorname, name as Nachname
attributes: [
['forename', 'PAPPS286'],
['name', 'Nachname'],
['birthdate', 'PADPS60']
],
include: [{ model: SurveyResult, attributes: ['result'] }]
}).map(user => user.toJSON())
res.send({
transaction
}
)
}
这是我从函数中获得的 JSON
:
{
"transaction": [
{
"PAPPS286": "Tes",
"Nachname": "Josef",
"PADPS60": null,
"SurveyResults": [ {
"result": {
"name": "blau",
"email": "mail",
"birthdate": "01.02.1990"
}
}]
},
{
"PAPPS286": "Dampf",
"Nachname": "Hans",
"PADPS60": null,
"SurveyResults": [
{
"result": {
"name": "blau",
"email": "mail",
"birthdate": "01.02.1990"
}
}
]
},
]
},
这是我需要的 JSON
表单:
{
"transaction": [
PAD{
"PAPPS286": "Tes",
"Nachname": "Josef",
"PADPS60": null,
"MH": {
"name": "blau",
"email": "mail",
"birthdate": "01.02.1990"
},
PAD{
"PAPPS286": "Dampf",
"Nachname": "Hans",
"PADPS60": null,
"MH": {
"name": "blau",
"email": "mail",
"birthdate": "01.02.1990"
}
},
]
},
也许有一种方法可以在我取回 JSON 后对其进行修改。但我不知道这是如何运作的。
最佳答案
下面的 map
符合我认为您正在寻找的内容。您可能需要修改它,特别是根据 key 访问所需的变量。 (t.PAPPS286
和 t.PADPS60
)
此外,我只获取第一个调查结果SurveyResults
。如果没有或超过 1 个,则不确定您想要什么。
var obj = {
"transaction": [{
"PAPPS286": "Tes",
"Nachname": "Josef",
"PADPS60": null,
"SurveyResults": [{
"result": {
"name": "blau",
"email": "mail",
"birthdate": "01.02.1990"
}
}]
},
{
"PAPPS286": "Dampf",
"Nachname": "Hans",
"PADPS60": null,
"SurveyResults": [{
"result": {
"name": "blau",
"email": "mail",
"birthdate": "01.02.1990"
}
}]
},
]
}
obj.transaction = obj.transaction.map((t) => {
return Object.assign({
"PAPPS286": t.PAPPS286,
"Nachname": t.Nachname,
"PADPS60": t.PADPS60,
"MH": {
"name": t.SurveyResults[0].result.name,
"email": t.SurveyResults[0].result.email,
"birthdate": t.SurveyResults[0].result.birthdate
}
})
})
console.log(obj);
关于mysql - 收到sequelize的响应后修改JSON,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54693663/