mysql - 如何获取过去7天的总用户平均时间

Question

我想获得过去 7 天的每天总用户平均使用时间，我为每个用户平均时间编写了 SQL，它非常完美，但我在 LARAVEL SQL 函数中遇到了问题，请帮助修复此 SQL。

$currentTime = Carbon::today();

    $userUsage = DB::table('active_user')
                ->select(DB::raw('acu_name as name'),
                    DB::raw('u_fname as fname'),
                    DB::raw('AVG(TIMESTAMPDIFF(MINUTE,acu_at,acu_et)) as averageTime'),
                    DB::raw('count(*) as number'))
                ->join('u_info_one', 'active_user.acu_name', '=', 'u_info_one.u_email')
                ->whereDate('acu_at', '<=', $currentTime)
                ->groupBy('acu_name')
                ->get();

Answer 1

为此，您需要使用GROUP BY，例如:

$userUsage = DB::table('active_user')
                ->select(DB::raw('acu_name as name'),
                    DB::raw('u_fname as fname'),
                    DB::raw('AVG(TIMESTAMPDIFF(MINUTE,acu_at,acu_et)) as averageTime'),
                    DB::raw('count(*) as number'))
                ->join('u_info_one', 'active_user.acu_name', '=', 'u_info_one.u_email')
                ->whereDate('acu_at', '<=', $currentTime)
                ->groupBy('acu_name', DB::raw('DATE(acu_at)'))
                ->get();

更新

如果您只需要所有用户的每日平均值，您可以从分组依据中删除acu_name，例如:

$userUsage = DB::table('active_user')
                ->select(DB::raw('acu_name as name'),
                    DB::raw('u_fname as fname'),
                    DB::raw('AVG(TIMESTAMPDIFF(MINUTE,acu_at,acu_et)) as averageTime'),
                    DB::raw('count(*) as number'))
                ->join('u_info_one', 'active_user.acu_name', '=', 'u_info_one.u_email')
                ->whereDate('acu_at', '<=', $currentTime)
                ->groupBy(DB::raw('DATE(acu_at)'))
                ->get();