我的表中有这些数据:
numb m value
8070 1 7.63
NULL 1 7.64
NULL 1 7.65
8070 2 7.939
8070 2 7.935
8070 2 7.941
NULL 3 7.62
8070 4 7.92
8070 4 7.935
对于每个m
,我需要MIN(value)
和MAX(value)
,并且如果有一个值
code> 没有 numb
(NULL),那么那些有 numb
的应该被忽略。
所以我应该得到以下结果:
numb m value
NULL 1 7.64
NULL 1 7.65
8070 2 7.935
8070 2 7.941
NULL 3 7.62
8070 4 7.92
8070 4 7.935
我尝试了很多不同的方法,但似乎没有任何效果,而且我不知道如何查找相关信息。你能指出我正确的方向吗?
更新: 要获取值的数量,如下所示:
COALESCE(
IF(
COUNT(
CASE
WHEN m IN (2, 4)
THEN value
ELSE
CASE
WHEN m IN (1, 3) AND numb IS NULL
THEN value
END
END
) = 0,
NULL,
COUNT(
CASE
WHEN m IN (2, 4)
THEN value
ELSE
CASE
WHEN m IN (1, 3) AND numb IS NULL
THEN value
END
END
)
),
COUNT(
CASE
WHEN m IN (1, 3)
AND numb IS NOT NULL
THEN value
END
)
) AS cnt
最佳答案
这个查询应该会给你你想要的结果。它有两层嵌套派生表。第一个:
SELECT m,
MIN(CASE WHEN numb IS NULL THEN value END) AS min_null,
MAX(CASE WHEN numb IS NULL THEN value END) AS max_null,
MIN(CASE WHEN numb IS NOT NULL THEN value END) AS min_normal,
MAX(CASE WHEN numb IS NOT NULL THEN value END) AS max_normal
FROM numbers
GROUP BY m;
计算每个m
值的最小值和最大值,具体取决于numb
是数字还是NULL
。在下一个级别,
SELECT m,
COALESCE(min_null, min_normal) AS min_value,
COALESCE(max_null, max_normal) AS max_value
FROM (... query 1...)
我们使用计算要使用的适当的最小值和最大值(如果有 NULL
值,我们使用该值,否则我们使用与 numb
数值关联的值>)。最后,我们将数字表JOIN
到查询2的结果,为每个m
值找到适当的numb
值:
SELECT n.numb, n.m, n.value
FROM numbers n
JOIN (... query 2 ...) num ON num.m = n.m AND (num.min_value = n.value OR num.max_value = n.value)
ORDER BY n.m, n.value
输出:
numb m value
null 1 7.64
null 1 7.65
8070 2 7.935
8070 2 7.941
null 3 7.62
8070 4 7.92
8070 4 7.935
完整查询:
SELECT n.numb, n.m, n.value
FROM numbers n
JOIN (SELECT m,
COALESCE(min_null, min_normal) AS min_value,
COALESCE(max_null, max_normal) AS max_value
FROM (SELECT m,
MIN(CASE WHEN numb IS NULL THEN value END) AS min_null,
MAX(CASE WHEN numb IS NULL THEN value END) AS max_null,
MIN(CASE WHEN numb IS NOT NULL THEN value END) AS min_normal,
MAX(CASE WHEN numb IS NOT NULL THEN value END) AS max_normal
FROM numbers
GROUP BY m) n) num ON num.m = n.m AND (num.min_value = n.value OR num.max_value = n.value)
ORDER BY n.m, n.value
关于MySQL CASE WHEN numb IS NULL 忽略记录 WHERE numb IS NOT NULL,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55022725/