如何通过 $sql 和 $sqll 一起回显数据,任何人都可以解决这个问题
$sql = "SELECT chat_msg, chat_date FROM chat WHERE chat_room_id = '13' AND userid = '13'";
$sqll = "SELECT chat_msg, chat_date FROM chat WHERE chat_room_id = '13' AND userid = '15'";
$result = $conn->query($sql);
$resultt = $conn->query($sqll);
if ($result->num_rows > 0 && $resultt->num_rows > 0){
// output data of each row
while($row = $result->fetch_assoc() && $roww = $resultt->fetch_assoc()) {
echo "NO" . $row["chat_msg"]. $roww["chat_msg"]. "<br>";
}
} else {
echo "0 results";
}
最佳答案
您最好不要合并两个结果,而是在单个查询中查询所有相关行:
$sql =
"SELECT chat_msg, chat_date FROM chat WHERE chat_room_id = '13' AND userid IN ('13', '15')";
关于php - 如何在php中进行sql查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55332961/