我正在使用 10.1.39-MariaDB - mariadb.org 二进制文件
,我有下表:
| id | date | ticker | close |
|-------|---------------------|--------|-----------|
| 39869 | 2019-09-18 00:00:00 | AAPL | 221.96160 |
| 39870 | 2019-09-17 00:00:00 | AAPL | 220.70000 |
| 39871 | 2019-09-16 00:00:00 | AAPL | 219.90000 |
| 39872 | 2019-09-13 00:00:00 | AAPL | 218.75000 |
| 39873 | 2019-09-12 00:00:00 | AAPL | 223.09000 |
| 39874 | 2019-09-11 00:00:00 | AAPL | 223.59000 |
| 39875 | 2019-09-10 00:00:00 | AAPL | 216.70000 |
我有两个查询,其中计算 52 周
的指标,第二个查询计算 20 天
的聚合指标:
52 周:
SELECT
Y.*
FROM
(
SELECT
MAX(CLOSE) AS week_52_High,
DATE AS week_52_High_date,
MIN(CLOSE) AS week_52_Low,
DATE AS week_52_Low_date,
AVG(CLOSE) AS week_52_Avg
FROM
`prices`
WHERE
DATE >= DATE(NOW()) - INTERVAL 52 WEEK AND ticker = "AAPL") Y
LEFT JOIN prices tmax52 ON
tmax52.date = Y.week_52_High_date AND tmax52.close = week_52_High
LEFT JOIN prices tmin52 ON
tmin52.date = Y.week_52_Low_date AND tmin52.close = week_52_Low
LEFT JOIN prices tavg52 ON
tavg52.close = week_52_Avg
20 天
SELECT
Y.*
FROM
(
SELECT
MAX(CLOSE) AS day_20_High,
DATE AS day_20_High_date,
MIN(CLOSE) AS day_20_Low,
DATE AS day_20_Low_date,
AVG(CLOSE) AS day_20_Avg
FROM
`prices`
WHERE
DATE >= DATE(NOW()) - INTERVAL 20 DAY AND ticker = "AAPL") Y
LEFT JOIN prices tmax20 ON
tmax20.date = Y.day_20_High_date AND tmax20.close = day_20_High
LEFT JOIN prices tmin20 ON
tmin20.date = Y.day_20_Low_date AND tmin20.close = day_20_Low
LEFT JOIN prices tavg20 ON
tavg20.close = day_20_Avg
两个查询都会计算每个收盘价的最小/最大/平均值,并附上发生这种情况的日期。
有什么建议如何合并这两个查询以将所有内容合并到 1 个输出中吗?
感谢您的回复!
最佳答案
您的第一个问题是您的查询实际上不起作用。获取high
和low
值的日期的正确方法如下。请注意,尝试获取平均收盘价是没有意义的,因为股票不太可能以该价格收盘。
SELECT
Y.day_20_High,
tmax20.DATE AS day_20_High_date,
Y.day_20_Low,
tmin20.DATE AS day_20_Low_date,
Y.day_20_Avg
FROM
(
SELECT
MAX(CLOSE) AS day_20_High,
MIN(CLOSE) AS day_20_Low,
ROUND(AVG(CLOSE),2) AS day_20_Avg
FROM
`prices`
WHERE
DATE >= CURDATE() - INTERVAL 20 DAY AND ticker = "AAPL") Y
LEFT JOIN prices tmax20 ON tmax20.close = Y.day_20_High
LEFT JOIN prices tmin20 ON tmin20.close = Y.day_20_Low
输出(对于我的示例数据)
day_20_High day_20_High_date day_20_Low day_20_Low_date day_20_Avg
107.50 2019-09-20 101.10 2019-09-10 104.05
更正查询后,您现在只需 JOIN
到 52 周数据的同一查询即可:
SELECT
Y20.day_20_High,
tmax20.DATE AS day_20_High_date,
Y20.day_20_Low,
tmin20.DATE AS day_20_Low_date,
Y20.day_20_Avg,
Y52.week_52_High,
tmax52.DATE AS week_52_High_date,
Y52.week_52_Low,
tmin52.DATE AS week_52_Low_date,
Y52.week_52_Avg
FROM ((
SELECT
MAX(CLOSE) AS day_20_High,
MIN(CLOSE) AS day_20_Low,
ROUND(AVG(CLOSE),2) AS day_20_Avg
FROM
`prices`
WHERE
DATE >= CURDATE() - INTERVAL 20 DAY AND ticker = "AAPL") Y20
LEFT JOIN prices tmax20 ON tmax20.close = Y20.day_20_High
LEFT JOIN prices tmin20 ON tmin20.close = Y20.day_20_Low)
JOIN ((
SELECT
MAX(CLOSE) AS week_52_High,
MIN(CLOSE) AS week_52_Low,
ROUND(AVG(CLOSE),2) AS week_52_Avg
FROM
`prices`
WHERE
DATE >= DATE(NOW()) - INTERVAL 52 WEEK AND ticker = "AAPL") Y52
LEFT JOIN prices tmax52 ON tmax52.close = Y52.week_52_High
LEFT JOIN prices tmin52 ON tmin52.close = Y52.week_52_Low)
输出(对于我的示例数据)
day_20_High day_20_High_date day_20_Low day_20_Low_date day_20_Avg week_52_High week_52_High_date week_52_Low week_52_Low_date week_52_Avg
107.50 2019-09-20 101.10 2019-09-10 104.05 109.70 2019-08-24 100.00 2019-08-21 104.19
关于mysql - 合并两个使用不同时间范围的最小/最大/平均值查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58149717/