php - 当我将第二个表连接到第一个表时的总和不正确

标签 php mysql sql database

我有两个表:

  1. 订单(ID、网站、订单日期、shipping_fees、amazone_fees、totalAmount、profit_loss、processing_fees)
  2. orderItemDetails(id、orderId、product_name、product_expense)

enter image description here

我编写了这个查询来获取数据,但没有得到我想要的数据。因此,请更正我的查询,以便我获得上图中的数据。

SELECT 
    o.totalshippingfees,
    o.totalamazonefees,
    o.totalorderamount,
    o.totalprofitloss,
    o.totalprocessing_fees,
    oi.totalproductexpense,
    o.site
FROM (
    SELECT 
        orderdate,
        site,
        sum(orders.shipping_fees) as totalshippingfees,
        sum(orders.amazone_fees) as totalamazonefees,
        sum(orders.totalAmount) as totalorderamount,
        sum(orders.profit_loss) as totalprofitloss,
        sum(orders.processing_fees) as totalprocessing_fees
    FROM orders
    group by site
) as o
JOIN (
    SELECT 
        site,
        sum(orderItemDetails.product_expense) as totalproductexpense,
        sum(orders.shipping_fees) as totalshippingfees,
        sum(orders.amazone_fees) as totalamazonefees,
        sum(orders.totalAmount) as totalorderamount,
        sum(orders.profit_loss) as totalprofitloss,
        sum(orders.processing_fees) as totalprocessing_fees
    from orders 
    LEFT JOIN orderItemDetails ON orders.id = orderItemDetails.orderId 
    group by site
) as oi
WHERE MONTH(o.orderdate) = '".$monthNo."' AND YEAR(o.orderdate)= '".$monthyear[1]."'

最佳答案

如果我理解正确,您可以在 orders 上使用简单的按 site 分组,并在 orderItemDetails< 上按 site 分组 并在网站上加入他们。

select *
from (
    select 
      sum(shipping_fees) as totalshippingfees,
      sum(amazone_fees) as totalamazonefees,
      sum(totalAmount) as totalorderamount,
      sum(profit_loss) as totalprofitloss,
      sum(processing_fees) as totalprocessing_fees,
      site
    from orders 
    group by site
 ) d1
 join (
        select
            sum(product_expense) as totalproductexpense,
            site
        from orders o
        left join orderItemDetails od
        on o.id = od.orderId 
        group by site
      ) d2
on d1.site = d2.site

数据库 fiddle : https://www.db-fiddle.com/f/dkpctq1XrzB7bfsrojaZHd/2

更新:

您可以添加 where 条件进行日期过滤,如下所示:

select *
from (
    select 
      sum(shipping_fees) as totalshippingfees,
      sum(amazone_fees) as totalamazonefees,
      sum(totalAmount) as totalorderamount,
      sum(profit_loss) as totalprofitloss,
      sum(processing_fees) as totalprocessing_fees,
      site
    from orders 
    where MONTH(orderdate) = 10 AND YEAR(orderdate) = 2019
    group by site
 ) d1
 join (
        select
            sum(product_expense) as totalproductexpense,
            site
        from orders o
        left join orderItemDetails od
        on o.id = od.orderId 
        where MONTH(o.orderdate) = 10 AND YEAR(o.orderdate) = 2019
        group by o.site
      ) d2
    on d1.site = d2.site

数据库 fiddle : https://www.db-fiddle.com/f/kgZbS5U1oSgPAGX34URD22/0

关于php - 当我将第二个表连接到第一个表时的总和不正确,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58971441/

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