我有以下简化表格:
statistics
+-------------+-------------+---------------+
| type | itemnumber | borrowernumber |
+-------------+-------------+---------------+
| issue | 26191 | 11978 |
+-------------+-------------+---------------+
| issue | 26190 | 11979 |
+-------------+-------------+---------------+
items:
+-------------+-------------+
| itemnumber | bibliono |
+-------------+-------------+
| 26191 | 27 |
+-------------+-------------+
| 26190 | 28 |
+-------------+-------------+
biblio_metadata:
+-------------+----------------------------------------------------+
| bibliono | metadata |
+-------------+----------------------------------------------------+
| 27 | <?xml.. <datafield tag="082" ind1="0" ind2="4"> |
| <subfield code="a">005.133/M29</subfield> |
| </datafield> |
+-------------+----------------------------------------------------+
| 28 | <?xml.. <datafield tag="082" ind1="0" ind2="4"> |
| <subfield code="a">995.133/M29</subfield> |
| </datafield> |
+-------------+----------------------------------------------------+
borrowers
+-------------+-------------+
| borrowerno | sort1 |
+-------------+-------------+
| 11978 | CAS |
+-------------+-------------+
| 11979 | CBA |
+-------------+-------------+
我想通过mysql查询得到以下内容:
+-------------+------------+
| DDC Range | CAS | CBA |
+-------------+------------
| 001-100 | 1 | |
+-------------+------------
| 900-999 | | 1 |
+-------------+-----------+
我正在尝试找到正确的查询组合 - 如果是 mysql select 查询多列或任何其他关键字,但似乎无法获得正确的搜索术语。 我有以下组成的 mysql 查询,但无法传递第一列“CAS”并进一步查询其他 sort1(在此示例中为 CBA)。
SELECT CASE
WHEN ExtractValue(metadata, '//datafield[@tag="082"]/subfield[@code="a"]') REGEXP '^[0]{1}[0-9]{2}[^0-9]+.*' THEN "000-099"
WHEN ExtractValue(metadata, '//datafield[@tag="082"]/subfield[@code="a"]') REGEXP '^[9]{1}[0-9]{2}[^0-9]+.*' THEN "900-999"
ELSE "Others"
END as "DDC Range", count(borrowers.sort1)
from statistics s
LEFT JOIN items on (s.itemnumber=items.itemnumber)
LEFT JOIN biblio_metadata ON (items.biblionumber=biblio_metadata.biblionumber)
LEFT JOIN borrowers on (s.borrowernumber=borrowers.borrowernumber)
WHERE s.type = "issue"
AND borrowers.sort1="CAS"
GROUP BY Subjects
我正在调查这个COUNT(*) from multiple tables in MySQL但我不知道在哪里放置下一个查询,或者我想要到达的内容是否与上述链接相关。提前致谢
最佳答案
看起来您在查询中过滤掉了 borrowers.sort1="CAS"
的所有条目,但如果我理解正确的话,您将需要这些条目。
您不能按照问题中指定的方式执行所有连接,然后使用两个 case 语句吗?因为您似乎对每个主题的计数(*)感兴趣,所以您可以对它们进行求和。
也许尝试如下所示:
SELECT
CASE
WHEN ExtractValue(metadata, '//datafield[@tag="082"]/subfield[@code="a"]') REGEXP '^[0]{1}[0-9]{2}[^0-9]+.*' THEN "000-099"
WHEN ExtractValue(metadata, '//datafield[@tag="082"]/subfield[@code="a"]') REGEXP '^[9]{1}[0-9]{2}[^0-9]+.*' THEN "900-999"
ELSE "Others"
END as "DDC Range", count(borrowers.sort1),
sum(case when borrowers.sort1="CAS" then 1 else '' end) as 'CAS',
sum(case when borrowers.sort1="CBA" then 1 else '' end) as 'CBA'
from statistics s
LEFT JOIN items on (s.itemnumber=items.itemnumber)
LEFT JOIN biblio_metadata ON (items.biblionumber=biblio_metadata.biblionumber)
LEFT JOIN borrowers on (s.borrowernumber=borrowers.borrowernumber)
WHERE s.type = "issue"
GROUP BY Subjects
关于Mysql从多列中计数?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59863026/