mysql列表与查询逻辑的比较问题

Question

我正在比较 mysql 中的两个电子邮件地址列表 - listA 和 listB(两者都是 View )。最初，我想查找 listA 中不在 listB 中的所有电子邮件地址。我成功地做到了这一点:

$comparison_query = mysql_query("SELECT DISTINCT email_addresses FROM listA WHERE email_addresses NOT IN (SELECT DISTINCT email_addresses FROM listB) ORDER BY email_addresses");

现在，我想查找 listA 中不在 listB 或异常(exception)表中的所有电子邮件地址。我尝试这样做:

$comparison_query = mysql_query("SELECT email_addresses FROM listA WHERE email_addresses NOT IN (SELECT DISTINCT email_addresses FROM ((SELECT email_addresses FROM listB) UNION (SELECT email_addresses FROM exception))) ORDER BY email_addresses");

但是，这不起作用。谁能看出我哪里出了问题吗？

谢谢!

Answer 1

使用AND代替UNION

 mysql_query("SELECT email_addresses FROM listA
        WHERE email_addresses  NOT IN
        ( SELECT DISTINCT email_addresses FROM listB) AND 
         email_addresses  NOT IN
        (SELECT DISTINCT email_addresses FROM exception)) 
        ORDER BY email_addresses");