php - 使用 php 和 'if changed' 选项创建 xml

Question

我正在从 MySQL 数据库创建地址簿 xml 提要，一切正常，但我有一个部分标记，它获取姓氏的第一个字母并将其弹出到该标记中。我只想在它发生变化时显示它，但由于某种原因我的大脑今天早上不工作!

当前代码:

<?php

echo "<?xml version=\"1.0\" encoding=\"UTF-8\"?>";
echo "<data>";

do {

    $char = $row_fetch["surname_add"];
    $section = $char[0];

    //if(changed???){
        echo "<section><character>".$section."</character>";
    //}
    echo "<person>";
    echo "<name>".$row_fetch["firstname_add"]." ".$row_fetch["surname_add"]."</name>";
    echo "<title>".$row_fetch["title_add"]."</title>";
    echo "</person>";

    //if(){
        echo "</section>";
    //}


} while ($row_fetch = mysql_fetch_assoc($fetch));

echo "</data>";

?>

对此欢迎有任何帮助，不知道为什么我想不到!

Answer 1

如果您仍然想手动生成 XML，我想，这样的方法会起作用:

$section = "NoSectionStartedYet";
while ($row_fetch = mysql_fetch_assoc($fetch)) {

    $char = $row_fetch["surname_add"];
    if ($char[0] != $section)
    {
        if ($section != "NoSectionStartedYet")
        {
            echo "</section>";
        }
        $section = $char[0];
        echo "<section><character>".$section."</character>";
    }

    echo "<person>";
    echo "<name>".$row_fetch["firstname_add"]." ".$row_fetch["surname_add"]."</name>";
    echo "<title>".$row_fetch["title_add"]."</title>";
    echo "</person>";

}
echo "</section>";