mysql - 多对多hibernate映射和mysql脚本-持久化问题

Question

由于某种原因，这不会将任何内容持久保存到 tag_item 表中:

    Tag tag = new Tag();
    tag.setName("test");
    tag = (Tag) tagService.save(tag);

    Set<Tag> tags = new HashSet<Tag>();
    tags.add(tag);

    Item item = itemService.getByStringId(2);
    item.setTags(tags);
    itemService.save(item);

MySQL:

CREATE TABLE `tags` (
`tag_id` bigint(20) NOT NULL auto_increment,
`name` varchar(50) NOT NULL,
PRIMARY KEY (`tag_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_bin;

CREATE TABLE `tag_item` (
`tag_id` bigint(20) NOT NULL,
`item_id` bigint(20) NOT NULL,
PRIMARY KEY (`item_id`,`tag_id`),
KEY `FK_tag_item_tag_id` (`tag_id`),
KEY `FK_tag_item_item_id` (`item_id`),
CONSTRAINT `FK_tag_item_tag_id` FOREIGN KEY (`tag_id`) REFERENCES `tags` (`tag_id`),
CONSTRAINT `FK_tag_item_item_id` FOREIGN KEY (`item_id`) REFERENCES `items`    (`item_id`)
)ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_bin;

CREATE TABLE `items` (
`item_id` bigint(20) NOT NULL AUTO_INCREMENT,
`name` varchar(50) NOT NULL,
PRIMARY KEY (`item_id`)
) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8 COLLATE=utf8_bin;

Xml Hibernate 映射:

<id name="id" type="long" column="tag_id">
        <generator class="native"/>
</id>
    <property name="name" type="string" column="name"/>
    <set name="items" inverse="true" lazy="true" table="tag_item">
        <key>
              <column name="tag_id" not-null="true"/>
        </key>
        <many-to-many class="com.iteezy.shared.domain.Item">
              <column name="item_id" not-null="true"/>
        </many-to-many>
    </set>

<小时/>

<id name="id" type="long" column="item_id">
        <generator class="native"/>
</id>
    <property name="name" type="string" column="name"/>
    <set name="tags" inverse="true" lazy="true" table="tag_item">
        <key>
              <column name="item_id" not-null="true"/>
        </key>
        <many-to-many class="com.iteezy.shared.domain.Tag">
              <column name="tag_id" not-null="true"/>
        </many-to-many>
    </set>

Answer 1

您有双向多对多关系，因此您可以使用 8.5.3. Many-to-many 中的示例。另请参阅7.3.1. Sorted collections了解配置比较器的方法(尽管最好在数据库端使用 order-by 执行排序)。