我很困惑如何从 MySQL 数据库检索一些数据。我有这样的查询:
inspection_report table:
- Inspection_datetime
- Line
- Model
- Lot_no
- Serial_number
- Shift
- Range_sampling
- Accesories
- Acc_qty
Employee table:
- NIK
- name
SELECT DATE(A.Inspection_datetime) AS Date, A.Line,TRIM(A.Model) AS Model, A.Lot_no,
COUNT(A.Serial_number) AS Qty,GROUP_CONCAT(DISTINCT(A.Shift)) AS Shift,
IF(RIGHT(A.Range_sampling,4)='0000',10000,RIGHT(A.Range_sampling,4))-MID(A.Range_sampling,5,4)+1 AS Merchandise,
A.Accesories,A.Acc_qty,A.Range_sampling,B.name
FROM inspection_report A
LEFT JOIN Employee B
ON A.NIK=B.NIK
WHERE CHAR_LENGTH(A.Range_sampling) = 17 AND A.Issue='' AND A.Check='' AND A.Approve=''
GROUP BY A.Line, A.Model, A.Lot_no, A.Range_sampling
ORDER BY Date DESC,A.Line
我想显示来自 COUNT(A.Serial_number) AS Qty
的数据,其结果如下:
- 数量 = 20
- 数量 = 8
- 数量 = 32
我该如何检索它?
<小时/>结果如下:
|Date |Line |Model |Lot_no| Qty|Shift|Merchandise|Accesories|Acc_qty|Range_sampling|name |
+----------+-------+------+------+----+-----+-----------+----------+-------+--------------+-----+
|2011-05-12| fa 02 |BlaBla|021A | 20 | A | 200 | OK |11 | 1-200 |tom |
|2011-05-12| fa 15 | foo |021A | 8 | A | 200 | OK |11 | 1-200 |Bill |
|2011-05-12| fa 01 | Boom |021A | 32 | A | 200 | OK |11 | 1-200 | Jim |
最佳答案
执行GROUP BY
后,您可以使用HAVING
来设置要保留的聚合数据的条件:
SELECT DATE(A.Inspection_datetime) AS Date
, A.Line
, TRIM(A.Model) AS Model
, A.Lot_no
, COUNT(A.Serial_number) AS Qty
, GROUP_CONCAT(DISTINCT(A.Shift)) AS Shift
, IF( RIGHT(A.Range_sampling,4)='0000'
, 10000
, RIGHT(A.Range_sampling,4)
)
- MID( A.Range_sampling, 5, 4)
+ 1
AS Merchandise
, A.Accesories
, A.Acc_qty
, A.Range_sampling
, B.name
FROM inspection_report A
LEFT JOIN Employee B
ON A.NIK=B.NIK
WHERE CHAR_LENGTH(A.Range_sampling) = 17
AND A.Issue=''
AND A.Check=''
AND A.Approve=''
GROUP BY A.Line
, A.Model
, A.Lot_no
, A.Range_sampling
HAVING COUNT(A.Serial_number) IN (20, 8, 32)
ORDER BY Date DESC
, A.Line
<小时/>
最好不要对数字字段或计算结果使用 LIKE
。此条件:
Qty LIKE '20' OR Qty LIKE '8' OR Qty LIKE '32'
当Qty
是整数时可以写成:
Qty = 20 OR Qty = 8 OR Qty = 32
或等效为:
Qty IN (20, 8, 32)
关于Mysql:如何检索基于 COUNT() 结果的数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5959042/