php - 如何在我的查询中使用日期格式?

标签 php mysql sql

这适用于 phpmyadmin ,但当我在代码上使用时,会出现错误,错误显示,解析错误:语法错误,意外的“%”....

我的语法有什么问题>?

    <?php

$database =& JFactory::getDBO(); 

//Declare Variables
$user = JFactory::getUser();
$id = $user->get('id');
$name = $user->get('name');

// Display quizzes
echo "</br>";
echo "Quizzes History for : " ;
echo "<b>";
echo $name;
echo "</b>";


echo "</br>";
echo "</br>";

$database->setQuery(" SELECT distinct qui.title AS name,   

( SELECT GROUP_CONCAT(profiles.title)

  FROM jos_jquarks_users_profiles AS users_profiles    
  LEFT JOIN jos_jquarks_profiles AS profiles ON users_profiles.profile_id = profiles.id     
  WHERE users_profiles.user_id = sessionWho.user_id ) AS profile,    
   ( SELECT sum(score) 
 FROM jos_jquarks_quizzes_answersessions     

  WHERE quizsession_id = quizSession.id              AND status <> -1 ) AS score, 

( SELECT count(distinct question_id)              FROM jos_jquarks_quizzes_answersessions            
  WHERE quizsession_id = quizSession.id ) AS maxScore,            
DATE_FORMAT(quizSession.finished_on,'%M %d, %Y') 
 FROM jos_jquarks_quizsession AS quizSession  

LEFT JOIN jos_jquarks_users_quizzes AS users_quizzes ON users_quizzes.id = quizSession.affected_id    
LEFT JOIN jos_jquarks_quizzes AS qui ON users_quizzes.quiz_id = qui.id     
LEFT JOIN jos_jquarks_quizzes_answersessions AS quizSessAns ON quizSessAns.quizsession_id = quizSession.id 
LEFT JOIN jos_jquarks_sessionwho AS sessionWho ON sessionWho.session_id = quizSession.id        
LEFT JOIN jos_jquarks_users_profiles AS users_profiles ON users_profiles.user_id = sessionWho.user_id 
LEFT JOIN jos_jquarks_profiles AS profiles ON profiles.id = users_profiles.profile_id   
WHERE sessionWho.user_id =  ' .$id  " ) ;


if (!$database->query()) { //write data and if error occurs alert
    echo "<script> alert('".$database->getErrorMsg()."'); </script>";
}

//var_dump($database);
$tableStyle = "padding: 5px;border:1px"; 
$tdStyle = "padding:5px "; 
$thStyle = "padding:7px ";

echo '<table style="' . $tableStyle . '" cellpadding="7" cellspacing="7">'; 
echo "<tr> <th style=align:center>Quiz Title </th><th style=align:center> Score </th><th>Maximum Score </th><th> Unanswered </th> <th>Finished On </th></tr>"; 

$row = $database->loadRowList();
foreach($row as $valuearray)
{
echo '<tr style=" align="center">';
foreach($valuearray as $field)
{

echo "<td>$field</td>";
}
echo "</tr>";
}
echo "</table>";

?>

最佳答案

你必须避开 ' 标记。 所以而不是

    DATE_FORMAT(quizSession.finished_on,'%M %d, %Y')

尝试

    DATE_FORMAT(quizSession.finished_on,\'%M %d, %Y\')

或者您可以只使用双引号 "来开始和结束字符串。

关于php - 如何在我的查询中使用日期格式?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/7072002/

相关文章:

mysql - 如何在MySQL中有效地从最大的N条记录中选择一条随机记录(不使用子查询)?

php - Symfony 5 - 使用 json_login 登录;登录过程不工作;

php - jquery跨域文件上传

php - Zend 选择 NOT IN

mysql - 无法打开CloudSQL binlog : "No such file or directory"

mysql - 尝试添加外键关系时mysql中的外键约束

php - Symfony LiipImagineBundle : filters not working for big images

php - 查询在 MySQL 中有效,但不适用于 Lumen/Laravel - 数值超出范围 : 1416

mysql - 计数函数返回零 - Mysql

SQL SELECT 语句,列名作为来自另一个表的值