php - mysql 从 json 结果

Question

我有一个 mysql 数据库，我需要从中获取其内容的 rss feed。 我需要 json 中的等效项:

mysql_select_db("mydb", $con);
$result = mysql_query("select date, title, description, url from blah where type = 'OFFERS' order by ref desc");

echo '<?xml version="1.0"?>
<rss version="2.0">
<channel>

<title></title>
<description></description>
<link></link>';

while($row = mysql_fetch_array($result))
  {
  echo "
  <item>
  <title>" . $row['title'] . "</title>
  <description>" . $row['description'] . "</description>
  <link>" . $row['url'] . "</link>
  <image>" . $row['date'] . "</image>
  </item>";
  }

到目前为止，我能开始工作的最接近的事情是:

<?php

$host="localhost"; 
$username="username"; 
$password="password"; 
$db_name="mydb"; 

$con=mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB");
$sql = "select date, title, description, url from blah where type = 'OFFERS' order by ref desc"; 
$result = mysql_query($sql);
$json = array();
if(mysql_num_rows($result)){
while($row=mysql_fetch_row($result)){
$json['title'][]=$row;
}
}

mysql_close($db_name);

echo json_encode($json); 

?>

如有任何帮助，我们将不胜感激

Answer 1

while ($row = mysql_fetch_assoc($result)) {
    $json[] = $row;
}

echo json_encode($json);