我正在尝试使用在 for 循环中递增的数组来查询我的数据库。由于某种原因,无论我做什么,这都不起作用,
我收到错误:
"You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')' at line 1"
当在 PHPMyAdmin 中查询数据库时,一切都很好,所以我假设 for 循环中的某些东西把它搞砸了。有什么想法吗?
我的代码:-
<?php
$submitclick=$_GET["submitclick"];
if($submitclick==1)
{
require('json.php');
$selec=$_GET["selec"];
$selec=str_replace("'","",$selec);
error_reporting(E_ALL);
mysql_connect("localhost", "seamus", "password") or
die("Could not connect: " . mysql_error());
mysql_select_db("seamus") or die("No such database");
$sql1 = sprintf("SELECT event FROM attends WHERE student = '%s'",$selec);
$result1 = mysql_query($sql1)
or die(mysql_error());
while ($row1 = mysql_fetch_array($result1))
{
$eve[] = $row1['event'];
}
for($f=0;$f<count($eve);$f++)
{
$sql = sprintf("SELECT event.id, teaches.staff, day, start, duration, room FROM event JOIN module ON (event.module=module.id) JOIN isin ON (event.id=isin.event) JOIN teaches ON (event.id=teaches.event) JOIN attends ON (event.id=attends.event) WHERE event.id = '%s')",$eve[$f]);
$result = mysql_query($sql)
or die(mysql_error());
$i=0;
while ($row = mysql_fetch_array($result))
{
$key =$row['day'].$row['start'];
$event[$key] = $row['id'];
$room[$row['id']] = $row['room'];
$lect[$row['id']] = $row['staff'];
$time[$i]= $row['duration'];
$i++;
}
}
$i=0;
最佳答案
这里有一个额外的括号,就在 '%s'
之后:
... WHERE event.id = '%s')",$eve[$f]);
只需将其删除即可工作。
关于php - php 中的 mysql 语法错误,输入 phpmyadmin 时工作正常,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10115656/