php - 在mysql上使用关系表选择时生成自定义数组

Question

当我想从数据库中选择数据时遇到问题。

这是我的查询

SELECT J.id as id_job, J.title as job_title, J.companies_id, C.name as company_name,J.created_at, L.name as Location,CL.postal_code, CL.address
                                FROM jobs J
                                INNER JOIN bla1 C ON ( C.id = J.company_id )
                                INNER JOIN bla2 CL ON ( CL.id = J.company_location_id )
                                INNER JOIN bla3 L ON ( L.id = CL.location_id )
                                WHERE J.status =1
                                AND C.status =2
                                And CL.status = 1
                                AND L.status = 1
                                ORDER BY J.created_at DESC
                                LIMIT 0 , 30

这是使用 var_dump() 进行查询的结果

["_result":protected]=>
  array(15) {
    [0]=>
    array(8) {
      ["id_job"]=>
      string(2) "27"
      ["job_title"]=>
      string(10) "YUYUYUYUYU"
      ["company_id"]=>
      string(1) "3"
      ["company_name"]=>
      string(16) "voyage indonesia"
      ["created_at"]=>
      string(19) "2012-10-03 09:35:37"
      ["Location"]=>
      string(4) "Bali"
      ["postal_code"]=>
      string(6) "989767"
      ["address"]=>
      string(11) "dimana mana"
    }
    [1]=>
    array(8) {
      ["id_job"]=>
      string(2) "23"
      ["job_title"]=>
      string(11) "OYEEEEAAHHH"
      ["company_id"]=>
      string(1) "3"
      ["company_name"]=>
      string(16) "voyage indonesia"
      ["created_at"]=>
      string(19) "2012-09-28 09:06:54"
      ["Location"]=>
      string(7) "Bandung"
      ["postal_code"]=>
      NULL
      ["address"]=>
      NULL
    }
    [2]=>
    array(8) {
      ["id_job"]=>
      string(2) "20"
      ["job_title"]=>
      string(14) "TKPDKJKLADKSJA"
      ["company_id"]=>
      string(1) "3"
      ["company_name"]=>
      string(16) "voyage indonesia"
      ["created_at"]=>
      string(19) "2012-09-20 09:24:50"
      ["Location"]=>
      string(7) "Bandung"
      ["postal_code"]=>
      NULL
      ["address"]=>
      NULL
    }
}
["_total_rows":protected]=>
  int(3)
  ["_current_row":protected]=>
  int(0)
  ["_as_object":protected]=>
  bool(false)

我的目标:数组索引为 8 的示例，或者比此代码更好的其他内容

array(8) {
          ["id_job"]=>
          string(2) "27"
          ["job_title"]=>
          string(10) "YUYUYUYUYU"
          ["company_id"]=>
          string(1) "3"
          Array ( [companies] => array(1) {
          ["company_name"]=>
          string(16) "voyage indonesia"
          })
          ["created_at"]=>
          string(19) "2012-10-03 09:35:37"
          ["Location"]=>
          string(4) "Bali"
          ["postal_code"]=>
          string(6) "989767"
          ["address"]=>
          string(11) "dimana mana"
        }

company_id为关系表数据库表bla1， 我想在关系表中给出数组，这样我就可以轻松解析数据， 喜欢 array('bla1' = > array('company_id',1)); 有什么建议吗？

Answer 1

我想这就是你想要的。

 array[$row_id] = $row;