php - MySQL行已插入但未保存？

Question

我正在从PHP向MySQL表中插入一行，并在插入后立即运行查询，以获取刚刚插入的行的键值，如下所示：

$stmt = $this->db->prepare("INSERT INTO user(vFirstName, vLastName, vEmail, vPassword, iSkilllevelid, vTournaments, vDays, dAddedDate, eStatus) VALUES (?,?,?,?,4,'Pick-Up','Saturday',NOW(),'Active')");
$stmt->bind_param("ssss", $firstName, $lastName, $email, $pwd);
$stmt->execute();
$stmt->close();

$stmt = $this->db->prepare('SELECT iUserId FROM user WHERE vEmail=?');
$stmt->bind_param("s", $email);
$stmt->execute();
$stmt->bind_result($iUserId);
while ($stmt->fetch()) {
    break;
}

执行此代码后，$iUserId具有正确的自动递增键值（例如1143），但是当我实际查看数据库表时，具有该键的行（1143）不存在。那怎么可能？

Answer 1

插入后，不要从表中进行选择，而应使用mysqli::$insert_id：

$stmt = $this->db->prepare('
  INSERT INTO user
    (vFirstName, vLastName, vEmail, vPassword, iSkilllevelid,
       vTournaments, vDays, dAddedDate, eStatus)
  VALUES
    (?,?,?,?,4,"Pick-Up","Saturday",NOW(),"Active")
');
$stmt->bind_param('ssss', $firstName, $lastName, $email, $pwd);
$stmt->execute();
$iUserId = $this->db->insert_id;
$stmt->close();

至于为什么插入的数据没有从其他连接中出现，看来您的事务未提交：

$this->db->commit();