php - 将两个 SELECT 连接到一个 mysql_query

Question

有问题，我需要加入 2 个 SELECT。我有这段代码，但它将所有从 $age 到页面末尾的内容，我需要它与其他结果位于同一行

<?php
mysql_connect("***", "***", "***") or die(mysql_error());
mysql_select_db("***");

$result = mysql_query("SELECT * FROM business");
$age = mysql_query("SELECT DATEDIFF( CURRENT_DATE, founded ) as date_difference FROM business");

while($row = mysql_fetch_array($result))
  {
 ?><li class="onebusiness <?php echo $row['category']?>"><a href="<?php
  echo $row['link'];?>"><img src="<?php
  echo $row['img'];?>" height="125" width="125"/><p class="name"><?php
  echo $row['name'];?></p><p class="age"><?php
  echo $row['founded'];?></p></a></li><?php
  }

while($row = mysql_fetch_array($age))
  {
 ?><p class="age"><?php echo $row['date_difference']?></p><?php
  }
mysql_close();
?> 

Answer 1

你可以这样做:

mysql_query("SELECT *, DATEDIFF( CURRENT_DATE, founded ) as date_difference FROM business");