我有两个结构相同的表。 Table1 保存经过审核的数据，table2 保存其余数据。
表1
+------+--------+---------------+--------+-----------+ | "id" | "name" | "description" | "type" | "country" | +------+--------+---------------+--------+-----------+ | "1" | "a" | "x" | "1" | "US" | | "2" | "b" | "x" | "1" | "UK" | +------+--------+---------------+--------+-----------+
Table 2
+------+-----------+-----------------+--------+-----------+----------+ | "id" | "name" | "description" | "type" | "country" | "status" | +------+-----------+-----------------+--------+-----------+----------+ | "1" | "Title 1" | "Description 1" | "1" | "US" | "0" | | "2" | "Title 2" | "Description 2" | "10" | "UK" | "0" | +------+-----------+-----------------+--------+-----------+----------+
I run the below sql in order to update table 1 with data from table 2, and it works well. The only problem is, I need to specify the id in both places. If I were to specify it only in one place, where would it go?
UPDATE table1 dest,
(SELECT name,
description
FROM table2
WHERE id = 1) src
SET dest.name = src.name,
dest.description = src.description
WHERE dest.id = 1;
事情的发展方式是:
UPDATE table1 SET name AND description =
(
SELECT name, description from table2
WHERE id=1 AND country=us and type=10
) WHERE id=idfromselect AND country=countryfromselect AND type=typefromselect
我不知道将id和剩余条件放在哪里。你能帮忙吗？
最佳答案
将其作为联接进行，将 id 放入联接条件中，然后仅检查 WHERE 子句中的 id。
类似这样的:-
UPDATE table1 dest INNER JOIN table2 src ON dest.id = src=id
SET dest.name = src.name, dest.description = src.description
WHERE dest.id=1 ;
任何其他限制都可以添加到 WHERE 子句中
关于MySql 使用另一个表中的数据更新一个表，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/16916685/