我目前正在尝试从 SQL 数据库中回显信息,我必须对这些信息进行编码才能有效地将其写入表中;现在,当我尝试回显信息时,在对其进行解码时,页面没有显示任何内容,我不完全确定此时我做错了什么。
<?php
$type = $_SESSION['SESS_ACC_TYPE'];
$login = $_SESSION['SESS_LOGIN_NAME'];
$log = base64_decode(''.$row['log'].'');
if ($type == '2') {
$qry = "SELECT log FROM logs ";
$result = mysqli_query($GLOBALS["___mysqli_ston"], $qry);
while($row = mysqli_fetch_assoc($result)){
echo ''.$log.'';
}
}
if ($type == '1') {
$qry = "SELECT log FROM logs WHERE login = '.$login.'";
$result = mysqli_query($GLOBALS["___mysqli_ston"], $qry);
while($row = mysqli_fetch_assoc($result)){
echo ''.$log.'';
}
} else {
//do nothing
}
?>
最佳答案
您的代码有很多错误:
我修好了它们。
$type = $_SESSION['SESS_ACC_TYPE'];
$login = $_SESSION['SESS_LOGIN_NAME'];
if ($type == '2') {
$qry = "SELECT `log` FROM `logs`;";
}
if ($type == '1') {
$qry = "SELECT `log` FROM `logs` WHERE `login` = '" . $login . "';";
}
$result = mysqli_query($GLOBALS["___mysqli_ston"], $qry);
while($row = mysqli_fetch_assoc($result)) {
echo base64_decode($row['log']);
}
关于php - 无法从 mysqli 进行 Base64 解码,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17119535/