我有以下 MySQL 查询;
SELECT *, @rownum := @rownum + 1 from
(
SELECT (display_name) 'Author',
IFNULL(ROUND(SUM(balance.meta_value),2),2) 'Balance'
FROM posts p
JOIN users u
ON p.post_author = u.ID
JOIN postmeta odd ON p.ID = odd.post_id AND odd.meta_key = 'odd' AND odd.meta_value >= 1.5
LEFT JOIN postmeta balance
ON p.ID = balance.post_id AND balance.meta_key = 'balance'
WHERE p.post_status = 'publish' and p.post_author = 'User1'
GROUP BY u.ID
ORDER BY Balance DESC
)x, (SELECT @rownum := 0) r
生成下表;
Users Balance @rownum := 0 @rownum := @rownum + 1
User1 5.88 0 1
User2 -23.41 0 2
如何回显第一个用户最后一列的值(其中 [@rownum := @rownum + 1] = 1。
谢谢
最佳答案
$result = mysql_query("your's sql query");
$row = mysql_fetch_array($result);
echo $row[2];
关于php - 回显 MySQL 查询的单个结果,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17202053/