我有一个包含别名的 SQL 查询。问题是,当我尝试获取列的值时,它没有显示正确的值:
$sql = "SELECT p.ID, p.ProfileID, p.ModuleID, p.View, p.Add, p.Edit, p.Delete, m.Name, m.ID FROM permission AS p, module AS m WHERE p.ModuleID = m.ID ORDER BY p.ProfileID ASC, m.Name ASC";
$result = array();
$i = 0;
foreach ($this->dbconnect->query($sql) as $row)
{
$result[$i] = array(
'ID' => $row['p.ID'],
'ProfileID' => $row['p.ProfileID'],
'ModuleID' => $row['p.ModuleID'],
'View' => $row['p.View'],
'Add' => $row['p.Add'],
'Edit' => $row['p.Edit'],
'Delete' => $row['p.Delete']);
$i += 1;
}
当数据库中实际值为 10 时,运行不会显示任何值。
如果我将上面的代码更改为以下内容:
$sql = "SELECT p.ID, p.ProfileID, p.ModuleID, p.View, p.Add, p.Edit, p.Delete, m.Name, m.ID FROM permission AS p, module AS m WHERE p.ModuleID = m.ID ORDER BY p.ProfileID ASC, m.Name ASC";
$result = array();
$i = 0;
foreach ($this->dbconnect->query($sql) as $row)
{
$result[$i] = array(
'ID' => $row['ID'],
'ProfileID' => $row['ProfileID'],
'ModuleID' => $row['ModuleID'],
'View' => $row['View'],
'Add' => $row['Add'],
'Edit' => $row['Edit'],
'Delete' => $row['Delete']);
$i += 1;
}
神奇的是,运行显示的是m.ID
的值,而不是p.ID
。很奇怪为什么第一个例子是错误的。我在这里遗漏了什么吗?
最佳答案
你应该是这样的......
SELECT p.ID as p_ID, ...
还有
'ID' => $row['p_ID'],
关于php - 当 SQL 查询有别名时获取列值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18932205/