这是我的代码
<?php
$page = isset($_POST['page']) ? intval($_POST['page']) : 1;
$rows = isset($_POST['rows']) ? intval($_POST['rows']) : 10;
$offset = ($page-1)*$rows;
$result = array();
include 'conn.php';
//$rs1 = "select CONCAT(id,' ',firstname) AS password FROM users";
$rs = mysql_query("select count(*) from users");
$row = mysql_fetch_row($rs);
$result["total"] = $row[0];
$rs = mysql_query("select * from users limit $offset,$rows");
$items = array();
while($row = mysql_fetch_object($rs)){
array_push($items, $row);
}
$result["rows"] = $items;
echo json_encode($result);
?>
我的输出是
ID firstname lastname password*
1 john abc
2 don def
3 man ghi
我想要使用 id+名字 来取消密码。请帮助我完成上面的代码...
最佳答案
更正的代码:
<?php
$page = isset($_POST['page']) ? intval($_POST['page']) : 1;
$rows = isset($_POST['rows']) ? intval($_POST['rows']) : 10;
$offset = ($page-1)*$rows;
$result = array();
include 'conn.php';
//$rs1 = "select CONCAT(id,' ',firstname) AS password FROM users";
$rs = mysql_query("select count(*) from users");
$row = mysql_fetch_row($rs);
$result["total"] = $row[0];
$rs = mysql_query("select *, CONCAT(id, firstname, password) AS pwd from users limit $offset,$rows");
$items = array();
while($row = mysql_fetch_object($rs)){
array_push($items, $row);
}
$result["rows"] = $items;
echo json_encode($result);
?>
关于php-mysql : concat query in below code and manipulation of code,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19020312/