mysql - 从多个表中选择与 JOIN 比较

Question

我需要显示当前用户的所有赛程(谁与谁比赛)，所以我编写了 SQL 查询

SELECT 
  fixture.*
FROM
  sport_team_player AS team_player, sport_team AS team 
INNER JOIN sport_fixture AS fixture 
  ON (`team_player`.`team_id` = fixture.`team1_id` OR `team_player`.`team_id` = fixture.`team2_id`)
WHERE 
  team_player.`team_id` = team.`team_id` AND team_player.`player_id` = '16'

这不起作用并告诉我 team_player.team_id 不存在

但是如果我加入第二个表而不是从多个表中进行选择，它就可以正常工作。

PS。这不是编写此类查询的最佳方式，但它是由 ORM 模块生成的。

编辑:

结果将是夹具数据列表，例如

------------------------------
|fixture_id|team1_id|team2_id|
------------------------------
|1         | 2      | 3      |
------------------------------

Answer 1

试试这个。应该产生与您相同的查询；

SELECT fixture.*
FROM  sport_team_player AS team_player
JOIN  sport_team AS team 
ON    team_player.`team_id` = team.`team_id` AND team_player.`player_id` = '16'
INNER JOIN sport_fixture AS fixture 
ON (`team_player`.`team_id` = fixture.`team1_id` 
     OR `team_player`.`team_id` = fixture.`team2_id`) 

在构建连接时，不应混淆这两种表示法。您用来连接 team_player 和 team 的逗号，以及随后对内部连接的调用，很可能会触发未知列错误。