php - mysqli中的mysql_result替换

Question

因此，我正在将整个站点迁移到mysqli_ *的过程中，遇到了我找不到的第一个问题。基本上，我有一个password_reset表单，只有具有链接的用户才能访问。用户进入password_reset.php网站后，需要先输入临时密码，然后才能更改密码。我使用mysql_result来获取与通过http POST输入的用户名关联的临时密码。

$link_users = mysqli_connect("$host", "$username", "$password", "$db_name") or die("cannot connect");
$results=mysqli_query($link_users, "SELECT temporary_password FROM $tbl_name");
$row = mysqli_fetch_array($results);


$new_pass1 = $_POST['new1_password'];
$new_pass2 = $_POST['new2_password'];

$new_encrypted_mypassword = sha1($new_pass1);

$temp_pass = $_POST['temp_password'];
$username_fetch = $_POST['temp_username'];
$temppass_database = mysqli_result(mysqli_query($link_users, "SELECT temporary_password FROM $tbl_name WHERE temporary_password='$temp_pass' AND username='$username_fetch'"), 0);

if ($temp_pass == $temppass_database && $new_pass1 == $new_pass2){
mysqli_query($link_users, "UPDATE $tbl_name SET password='$new_encrypted_mypassword' WHERE username='$username_fetch'");
}

elseif ($temp_pass != $temppass_database){
echo '<div class="alert">Invalid Temporary Password or Username!</div>';
}

// Delete temporary password
if ($temp_pass == $temppass_database && $new_pass1 == $new_pass2 ) {
mysqli_query($link_users, "UPDATE $tbl_name set temporary_password = null WHERE username='$username_fetch'");
echo '<div class="alert">Updated Password!</div>';
}

希望您能找到一个易于实现的解决方案来代替mysql_results。如您在上面的代码中所见，我尝试使用mysqli_result，该方法不起作用！

编辑：如@randomizer建议；我更新了代码，并将mysql_result替换为：$temppass_database = mysqli_query($link_users, "SELECT temporary_password FROM $tbl_name WHERE temporary_password='$temp_pass' AND username='$username_fetch'")->fetch_object()->temporary_password;

谢谢您的帮助！

Answer 1

您可以使用mysqli_query("yourquery")->fetch_object()->password;

还可以查看准备好的语句，它将使您的工作更加轻松：
http://www.php.net/manual/en/mysqli.quickstart.prepared-statements.php