在 mysql 表中我有一组记录。我想获取它们,想像下面的 json 响应一样显示。
"results":[
{
"timestamp":"2014-03-04 17:26:14",
"id":"440736785698521089",
"category":"sports",
"username":"chetan_bhagat",
"displayname":"Chetan Bhagat"
}
我从数据库中获取了以上值,即时间戳、ID、类别、用户名。如何以上面的 json 响应形式显示结果?
更新:
我以这种方式获取数据:
$con = mysqli_connect('127.0.0.1', 'root', '', 'mysql');
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
return;
}
$today = date("Ymd");
$result = mysqli_query($con,"SELECT url,img_url,sentiment,title,category from frrole_cateogry_article where category='".$category."' AND today <= '".$today."' AND title != '' AND img_url != '' order by url desc limit 3 ");
while ($row = @mysqli_fetch_array($result))
{
$url = $row['url'];
$img_url = $row['img_url'];
$screen_name = $row['screen_name'];
}
最佳答案
试试这个...
$con = mysqli_connect('127.0.0.1', 'root', '', 'mysql');
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
return;
}
$today = date("Ymd");
$result = mysqli_query($con,"SELECT url,img_url,sentiment,title,category from frrole_cateogry_article where category='".$category."' AND today <= '".$today."' AND title != '' AND img_url != '' order by url desc limit 3 ");
while ($row = @mysqli_fetch_array($result))
{
json_encode($row);
}
关于php - 从数据库获取数据,将其显示为 json 响应,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22179470/