我无法思考如何做到这一点。我刚刚开始了解PDO,所以请原谅我的无知。我有一个表单,只需将一些帖子数据和图像数据插入 MySQL 数据库中。我有一个单独的表用于发布数据和图像数据。它们都有一个名为 postid
的行。帖子 postid
当前设置为 AUTO_INCRMENT
我只需要在图像和帖子表中使用相同的 postid
即可。然而,事情并不那么简单。图像并不总是添加到每个帖子中。因此,仅仅让两者同时递增是不够的。图像 postid
只需始终匹配相应的帖子 postid
我知道这不是一个关于代码问题的非常具体的问题,但希望我至少能得到一些好的见解。
除了将 postid
添加到 images
表之外,这是我当前正常运行的代码。
<!DOCTYPE html>
<html>
<body>
<center>
<form enctype="multipart/form-data" action="<?php echo htmlentities($_SERVER['PHP_SELF']);?>" method="post">
<input type="hidden" name="MAX_FILE_SIZE" value="99999999" />
<div><textarea name="entry" maxlength="600"></textarea></div>
<div><input name="userfile" type="file" /></div>
<div><input type="submit" value="Submit" /></div>
</form>
</body></html>
<?php
/*** check if a file was submitted ***/
if(!isset($_FILES['userfile']))
{
echo '<p>Please select a file</p>';
}
else
{
try {
upload();
/*** give praise and thanks to the php gods ***/
echo '<p>Thank you for submitting</p>';
}
catch(Exception $e)
{
echo '<h4>'.$e->getMessage().'</h4>';
}
}
?>
<?php
//Upload function
function upload(){
/*** check if a file was uploaded ***/
if(is_uploaded_file($_FILES['userfile']['tmp_name']) && getimagesize($_FILES['userfile']['tmp_name']) != false)
{
/*** get the image info. ***/
$size = getimagesize($_FILES['userfile']['tmp_name']);
/*** assign our variables ***/
$type = $size['mime'];
$imgfp = fopen($_FILES['userfile']['tmp_name'], 'rb');
$size = $size[3];
$name = $_FILES['userfile']['name'];
$maxsize = 99999999;
$poster = $_SESSION['username'];
$entry = $_POST['entry'];
/*** check the file is less than the maximum file size ***/
if($_FILES['userfile']['size'] < $maxsize )
{
/*** connect to db ***/
$dbh = new PDO("mysql:host=localhost;dbname=db_name", 'user', 'password');
/*** set the error mode ***/
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
/***sql query ***/
$stmt = $dbh->prepare("INSERT INTO images (image_type ,image, image_size, image_name) VALUES (? ,?, ?, ?)");
$stmt2 = $dbh->prepare("INSERT INTO posts (poster, entry) VALUES (? ,?)");
/*** bind the params ***/
$stmt->bindParam(1, $type);
$stmt->bindParam(2, $imgfp, PDO::PARAM_LOB);
$stmt->bindParam(3, $size);
$stmt->bindParam(4, $name);
$stmt2->bindParam(1, $poster);
$stmt2->bindParam(2, $entry);
/*** execute the query ***/
$stmt->execute();
$stmt2->execute();
}
else
{
/*** throw an exception is image is not of type ***/
throw new Exception("File Size Error");
}
}
else
{
// if the file is not less than the maximum allowed, print an error
throw new Exception("Unsupported Image Format and/or to large of a file.");
}
}
?>
最佳答案
- 执行插入帖子的查询,这会创建自动增量 ID。
- 使用
$dbh->lastInsertId()
获取这个新 ID。 - 准备图像查询并使用您在第 2 步中获得的 ID。
$stmt = $dbh->prepare("INSERT INTO posts (poster, entry) VALUES (?, ?)");
...
$stmt->execute();
$id = $dbh->lastInsertId();
$stmt = $dbh->prepare("INSERT INTO images (post_id, image_type, image, image_size, image_name) VALUES (?, ? ,?, ?, ?)");
$stmt->bindParam(1, $id);
...
$stmt->execute();
关于php - 在 PDO 语句中将相同的 id 分配给 2 个 MySQL 表行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22412711/