我的一个网站有一个注册脚本,我首先检查用户输入的电子邮件是否与数据库中的电子邮件匹配,如果匹配,则返回找到匹配项,并且不插入其将新帐户添加到数据库中。
- 我想知道是否有一种方法可以仅使用一个 mysql 连接对象来完成我正在做的事情,而不是初始化其中两个?
- 另外,我觉得我的代码非常困惑,并且希望获得一些关于如何更好地编写代码的额外意见。谢谢!
注意:验证 bool 值将在将来使用,因此请忽略它不执行任何操作的事实。
<?php
include '../portfolio/libraries/settings.php';
$first = $_POST['first'];
$middle = $_POST['middle'];
$last = $_POST['last'];
$email = $_POST['email'];
$emailFound = false;
$validation = true;
if ($_POST['type'] == "Student") {
$type = "0";
} else {
$type = "1";
}
$connect = mysqli_connect($HOST, $DB_USER, $DB_PASS, $DATABASE);
$connect1 = mysqli_connect($HOST, $DB_USER, $DB_PASS, $DATABASE);
$result = $connect1->prepare("SELECT email FROM AUTH_User WHERE email = ?");
$result->bind_param("s", $email);
$result->execute();
while($result->fetch()) {
$emailFound = true;
}
if (!$emailFound) {
if ($middle != "" || $middle != null) {
$query = "INSERT INTO AUTH_User (email, FirstName, MiddleName, LastName, is_faculty) VALUES (?, ?, ?, ?, ?)";
$stmt = $connect->prepare($query);
$stmt->bind_param("ssssi", $email, $first, $middle, $last, $type);
if ($stmt->execute() && $validation) {
echo "success";
}
} else {
$query = "INSERT INTO AUTH_User (email, FirstName, LastName, is_faculty) VALUES (?, ?, ?, ?)";
$stmt = $connect->prepare($query);
$stmt->bind_param("sssi", $email, $first, $last, $type);
if ($stmt->execute() && $validation) {
echo "success";
}
}
} else {
echo "found";
}
?>
最佳答案
您只能使用一个 $connect :)
也许我可以推荐您使用 PDO 进行查询:http://php.net/manual/en/book.pdo.php
我尝试用自己的经验清除你的代码,所以我没有更好的编码方法;)
include '../portfolio/libraries/settings.php';
$first = $_POST['first'];
$middle = $_POST['middle'];
$last = $_POST['last'];
$email = $_POST['email'];
$emailFound = false;
$validation = true;
$type = ($_POST['type'] == "Student")? 0 : 1 ;
$connect = mysqli_connect($HOST, $DB_USER, $DB_PASS, $DATABASE);
$result = $connect->prepare("SELECT email FROM AUTH_User WHERE email = ?");
$result->bind_param("s", $email);
$result->execute();
if(!$result->fetch()) {
if (isset($middle)) {
$query = "INSERT INTO AUTH_User (email, FirstName, MiddleName, LastName, is_faculty) VALUES (?, ?, ?, ?, ?)";
$stmt = $connect->prepare($query);
$stmt->bind_param("ssssi", $email, $first, $middle, $last, $type);
if ($stmt->execute() && $validation)
echo "success";
} else {
$query = "INSERT INTO AUTH_User (email, FirstName, LastName, is_faculty) VALUES (?, ?, ?, ?)";
$stmt = $connect->prepare($query);
$stmt->bind_param("sssi", $email, $first, $last, $type);
if ($stmt->execute() && $validation)
echo "success";
}
} else {
echo "found";
}
关于php - MySQL:使用相同连接对象的多个查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/24684520/