如果我有例如这两个表:
表1:
item category rating
------ -------- ------
table furniture 6
chair furniture 5
sofa furniture 7
bed furniture 4
apple food 7
banana food 6
spinach food 9
almonds food 8
happiness feeling 7
compassion feeling 6
love feeling 8
admiration feeling 7
和表2:
category minimum_rating
-------- --------------
furniture 6
food 8
feeling 7
并且考虑到每个类别的minimum_ rating值每个月都会修改,所以它会改变...我如何查询与table2相关的table1,以便它将采用该类别的minimum_ rating值item 并仅返回 table1 中评级等于或高于最低评级的那些项目?在这种情况下,查询预计返回:
item category rating
------ -------- ------
table furniture 6
sofa furniture 7
spinach food 9
almonds food 8
happiness feeling 7
love feeling 8
admiration feeling 7
非常感谢您的宝贵意见!
最佳答案
我认为您需要在两个表上进行JOIN
,如下所示。您也可以说 t1. rating = t2.minimum_ rating
select t1.*
from table1 t1 join table2 t2 on t1.category = t2.category
where t1.rating >= t2.minimum_rating;
关于mysql - SQL 查询返回列值高于某个最小值(具体取决于类别)的行?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32441423/