php - MySQL。从第二个表中选择最后一条记录(按创建时间)

Question

我有 2 个通过 userPhone 链接的表格。

表格用户

+-----------+-------+----------+--------+
| userPhone |  name | address  |  car   |
+-----------+-------+----------+--------+
| 096111111 | Bill  |  adr1    | {json} |
+-----------+-------+----------+--------+
| 097333333 | Max   |  adr2    | {json} |
+-----------+-------+----------+--------+
| 098888888 | Denis |  adr3    | {json} |
+-----------+-------+----------+--------+

表格订单

+-----------+---------+-------+-------+------------+
| userPhone | orderID | title | Descr | createdTS  |
+-----------+---------+-------+-------+------------+
| 096111111 | 59      | ttl1  | qqqq  | 1444999740 |
+-----------+---------+-------+-------+------------+
| 096111111 | 58      | ttl2  | wwww  | 1444999650 |
+-----------+---------+-------+-------+------------+
| 096111111 | 56      | ttl3  | rrrrr | 1444999600 |
+-----------+---------+-------+-------+------------+
| 096111111 | 57      | ttl4  | ttttt | 1444999540 |
+-----------+---------+-------+-------+------------+

我正在使用这样的请求，并且效果很好:

SELECT
      `users`.`userPhone`,
      `users`.`name`,
      `users`.`address`,
      `users`.`car`,
      (SELECT `title` FROM `orders` WHERE `orders`.`userPhone` = `users`.`userPhone` AND `orders`.`orderTS` < NOW()  ORDER BY `orders`.`createdTS` DESC LIMIT 1 ) as `title`,
      (SELECT `descr` FROM `orders` WHERE `orders`.`userPhone` = `users`.`userPhone` AND `orders`.`orderTS` < NOW()  ORDER BY `orders`.`createdTS` DESC LIMIT 1 ) as `descr`
FROM
              `users`
               LEFT JOIN `orders` USING (`userPhone`)
WHERE 
               `users`.`userPhone` like '%1111%';

但我认为额外的 SELECT 运行速度很慢。有没有更好更快的方法来解决？

如何使用另一个请求获得相同的结果(可能不需要额外的 SELECT)。

Answer 1

语法正确的 JOIN 将为您完成所有这些工作，无需内部 SELECT，而且速度更快。

SELECT
      `users`.`userPhone`,
      `users`.`name`,
      `users`.`address`,
      `users`.`car`,
      `orders`.`title`,
      `orders`.`desc`
FROM `users`
     JOIN `orders` ON `orders`.`phone` = `users`.`phone`
WHERE 
      `users`.`userPhone` like '%1111%'
  AND `orders`.`orderTS` < NOW() 
ORDER BY `orders`.`orderTS` DESC
LIMIT 1;

如果您想要所有这些记录，只需删除LIMIT 1