当我尝试将信息添加到数据库中时出现此错误:ошибка:
INSERT INTO `paper` (`PaperPrice`, `paperType`) VALUES (`666`, `PAPERBLA`)
Unknown column '666' in 'field list' Warning: mysql_query() [function.mysql-query]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\OpenServer\domains\localhost\menu.php on line 49
Warning: mysql_query() [function.mysql-query]: A link to the server could not be established in C:\OpenServer\domains\localhost\menu.php on line 49 Access denied for user 'ODBC'@'localhost' (using password: NO)
666
和 PAPERBLA
必须添加到列中,但它写到没有列“666”,这是我的 php 代码:
$table = 'paper';
$PriceTable = 'paperPrice';
$priceColumn = 'PaperPrice';
$typeColumn = 'paperType';
$host = 'localhost';
$username = 'root';
$password = '';
$dbname = 'info';
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("<table border='1'><tr><td>Connection failed: </td></tr>" . mysqli_connect_error());
}else{
echo"<table border='1'><tr><td>Connection success </td></tr>";
}
if(isset($_POST['submit'])){
$paperType = $_POST['t1'];
$paperRemove = $_POST['t2'];
$paperPrice = $_POST['t3'];
if($paperRemove=='' && $paperType!=''){
$sql = "INSERT INTO `$table` (`$priceColumn`, `$typeColumn`) VALUES (`$paperPrice`, `$paperType`)";
if (mysqli_query($conn, $sql)) {
echo 'добавлено "'.$paperType.'" в список" "'.$table.'"';
} else {
echo "ошибка: " . $sql . "<br>" . mysqli_error($conn);
}
}
最佳答案
您正在将反引号
与值一起使用。反引号用于标识符。
"INSERT INTO `$table` (`$priceColumn`, `$typeColumn`) VALUES (`$paperPrice`, `$paperType`)"
您必须使用 '
来表示字符串 -
"INSERT INTO `$table` (`$priceColumn`, `$typeColumn`) VALUES ($paperPrice, '$paperType')"
关于PHP mysql添加行错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35764214/