我有一些显示 HTML 表单的 PHP,如下所示: 然后当按下更新按钮时更新表中的信息。
我的问题是删除选项。每当我点击更新按钮时,信息都会成功更新,但我收到有关删除语句的错误消息:
代码如下: //连接到愿望 list 数据库的信息 $服务器名称 = ".com"; $db用户名 = ""; $密码=“”; $数据库名称 = "";
try {
// To connect to the database please
$conn = new mysqli($servername, $dbusername, $password, $dbname);
if ($conn->connect_error) {
die('Connect Error (' . $conn->connect_errno . ') '
. $conn->connect_error);
}
echo "Please click <strong><a href = 'http://eggcavity.com/add-wishlist'>here</a></strong> to add creatures to your wishlist.";
if(isset($_POST['submit'])){
$ids = $_POST['ids'];
// Prepare and bind the udpate statement
$sql2 = "UPDATE Wishlists SET Picture = ?, Stage = ?, Gender = ?, Frozen = ?, Notes= ? WHERE ID = ?";
$stmt2 = $conn->prepare($sql2);
$stmt2->bind_param('sssssi', $picture, $stage, $gender, $frozen, $notes, $id);
foreach($ids as $id){
$stagecode = $id . "stage";
$gendercode = $id . "gender";
$frozencode = $id . "frozen";
$notescode = $id . "notes";
$namecode = $id . "creature";
$stage = $_POST[$stagecode];
$Stage = $stage;
$gender = $_POST[$gendercode];
$frozen = $_POST[$frozencode];
$notes = $_POST[$notescode];
$name = $_POST[$namecode];
$sql1 = 'SELECT * FROM Creatures WHERE Name = "' . $name . '"';
$result = mysqli_query($conn, $sql1);
$row = $result->fetch_assoc();
$picture = $row["$stage"];
$stmt2->execute();
}
$theCount = 0;
foreach($_POST['delete'] as $selected){
$sql = "DELETE FROM Wishlists WHERE ID = ?";
$stmt = $conn->prepare($sql);
$stmt->bind_param('i', $selected);
$stmt->execute();
$theCount++;
}
echo "Your wishlist has been updated, and" .$theCount. " creature(s) has/have been removed from your wishlist.<br>Please click <a href='http://eggcavity.com/edit-wishlist'>here</a> to return to the edit page.";
} else {
// Get current user's username
$current_user = wp_get_current_user();
$username = $current_user->user_login;
$theDeleteCount = 0;
// Just display the form
$sql = 'SELECT Creature, Picture, Stage, Gender, Frozen, ID FROM Wishlists WHERE Username = "' . $username . '"';
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
echo '<form method="POST"><table><strong>' .
'<tr>' .
'<td></td>' .
'<td>Creature</td>' .
'<td>Stage</td>' .
'<td>Gender</td>' .
'<td>Frozen</td>' .
'</tr></strong>';
while($row = $result->fetch_assoc()) {
$creature = $row["Creature"];
$id = $row["ID"];
$picture = $row["Picture"];
$stage = $row["Stage"];
echo '<input name="ids[]" type="hidden" value="' . $id . '">' .
'<input name="' . $id . 'creature" type="hidden" value="' . $creature . '">' .
'<tr>' .
'<td rowspan="2"><img src="' . $picture . '"></td>' .
'<td>' . $creature . '</td>' .
'<td><select name="' . $id . 'stage">' .
'<option value ="' . $stage . '" selected>' . $stage . '</option>' .
'<option value = "Stage1">Stage1(Egg)</option>' .
'<option value = "Stage2">Stage2</option>' .
'<option value = "Stage3">Stage3</option>' .
'<option value = "Stage4">Stage4</option>' .
'</select></td>' .
'<td><select name="' . $id . 'gender">' .
'<option value ="' . $row["Gender"] . '" selected>' . $row["Gender"] . '</option>' .
'<option value = "Unspecified">Unspecified</option>' .
'<option value = "Female">Female</option>' .
'<option value = "Male">Male</option>' .
'</select></td>' .
'<td><select name="' . $id . 'frozen">' .
'<option value ="' . $row["Frozen"] . '" selected>' . $row["Frozen"] . '</option>' .
'<option value="Unspecified">Unspecified</option>' .
'<option value="Yes">Yes</option>' .
'<option value="No">No</option>' .
'</select></td>' .
'</tr>' .
'<tr>' .
'<td colspan="3">Notes: <input type="text" name="' . $id . 'notes" value="' . $row["Notes"] .'"></td>' .
'<td>' . 'Delete<br>' . '<input type="checkbox" name="creatures[]" value="' . $id . '"></td>' .
'</tr>';
}
echo '</table><input name="submit" type="submit" id="submit" value="Update"></form>';
} else {
echo "<br>You have no creatures in your wishlist.";
}
}
} catch (mysqli_sql_exception $e) {
throw $e;
}
// Close the connection to the database
$conn->close();
如果您可以帮助我找出我传递给 foreach() 语句的信息有什么问题:
foreach($_POST['delete'] as $selected){
我将永远感激不已。任何想法都有帮助。
我尝试了很多东西,其中很多都是在 stackoverflow 上找到的。我想我可能错过了一些小事和/或愚蠢的事情。我有另一个页面运行在复选框表单上,效果很好。
谢谢您,祝您有美好的一天!
最佳答案
包含要删除的生物 ID 的表单元素称为 creatures[]
,因此您需要处理该 POST 变量的内容,而不是 delete
- 甚至尽管 delete
是您想要做的。所以,也许是这样的:-
替换
$theCount = 0;
foreach($_POST['delete'] as $selected){
$sql = "DELETE FROM Wishlists WHERE ID = ?";
$stmt = $conn->prepare($sql);
$stmt->bind_param('i', $selected);
$stmt->execute();
$theCount++;
}
与
$theCount = 0;
$creatures=!empty( $_POST['creatures'] ) ? $_POST['creatures'] : false;
if( $creatures ) {
if( !is_array( $creatures ) ) $creatures=explode(',',$creatures);
foreach( $creatures as $id ){
$sql = "DELETE FROM Wishlists WHERE ID = ?";
$stmt = $conn->prepare($sql);
$stmt->bind_param('i', $id);
$stmt->execute();
$theCount++;
}
}
关于php - 带有复选框的 HTML 表单元素,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38582433/