mysql - 查询错误 (1248) : Every derived table must have its own alias INNER JOIN

Question

我想在 2 个表上使用 INNER JOIN，但是当我尝试以下任一语句时，我得到

Error in query (1248): Every derived table must have its own alias

SELECT DISTINCT(t2.col)
FROM tab2 as t2
INNER JOIN (
  SELECT DISTINCT(t1.col)
  FROM tab1 as t1
  WHERE t1.id>678 AND t1.id<5248
) ON t2.col=t1.col
WHERE t2.id>10 AND t2.id<3770

SELECT DISTINCT(col)
FROM tab2 as t2
INNER JOIN (
  SELECT DISTINCT(col)
  FROM tab1 as t1
  WHERE t1.id>678 AND t1.id<5248
) ON t2.col=t1.col
WHERE t2.id>10 AND t2.id<3770

有什么问题吗？

Answer 1

您需要向连接表添加别名:

SELECT DISTINCT(t2.col) FROM tab2 as t2 INNER JOIN (SELECT DISTINCT(t1.col) FROM tab1 as t1 WHERE t1.id>678 AND t1.id<5248) as t3 ON t2.col=t3.col WHERE t2.id>10 AND t2.id<3770