php - 尝试将两个数据库连接到一个 php 文件并存储用户 session

Question

好吧，所以我基本上尝试的是将两个数据库连接到我的index.php 文件，然后使用其中一个数据库来登录用户，并使用其他数据库之一来存储用户的 session 。

我不知道如何存储用户的 session 。我想要做的是显示用户信息，例如电子邮件和用户名之类的信息，然后当他们注销时，我希望该信息随着 session 而消失，但目前当用户登录时，信息保持不变老用户，它不会改变。

我在下面包含了我的代码。在我的代码中，当我提到 session 就像它的数据库一样时，那是因为我创建了一个名为 session 的数据库和表，而我的另一个数据库称为数据库，该表称为管理。

索引

<?php
 session_start();
$servername = "localhost";
$username = "root";
$password = "****";
$dbname = "database";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
     die("Connection failed: " . $conn->connect_error);
} 


if($_SERVER["REQUEST_METHOD"] == "POST") {
// username and password sent from form

$myusername = mysqli_real_escape_string($db,$_POST['username']);
$mypassword = mysqli_real_escape_string($db,$_POST['password']);

$sql = "SELECT id FROM admin WHERE username = '$myusername' and passcode = '$mypassword'";
$result = mysqli_query($db,$sql);
$row = mysqli_fetch_array($result,MYSQLI_ASSOC);
$active = $row['active'];

$count = mysqli_num_rows($result);

// If result matched $myusername and $mypassword, table row must be 1 row

if($count == 1) { 
$session_id = session_id(); 
$sql = "INSERT INTO session(session_id,username) VALUES('$session_id','$myusername')";
mysqli_query($db,$sql); 
header("Location: test2.php");
}else {
         $error = "";
      }
   }
?>

配置

<?php
   define('DB_SERVER', 'localhost');
   define('DB_USERNAME', 'root');
   define('DB_PASSWORD', '******');
   define('DB_DATABASE', 'database');
   $db = mysqli_connect(DB_SERVER,DB_USERNAME,DB_PASSWORD,DB_DATABASE);
?>

session

<?php
 include('config.php');
 session_start();

 $user_check = $_SESSION['myusername'];

 $ses_sql = mysqli_query($db,"select username from admin where username = '$user_check' ");

 $row = mysqli_fetch_array($ses_sql,MYSQLI_ASSOC);

 $login_session = $row['username'];

 ?>

测试 2 页面(这是我要登录的页面，以便显示用户信息。)

<?php
 session_start();
 include("config.php");

$servername = "localhost";
$username = "root";
$password = "*****";
$dbname = "database";
$dbname2 = "session";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname, $dbname2);
// Check connection
if ($conn->connect_error) {
     die("Connection failed: " . $conn->connect_error);
} 

$session_id = session_id(); 

$sql = "SELECT id, username, passcode, email, Address, City, Country, Zip, FirstName, LastName, About FROM admin WHERE username = (SELECT username FROM session WHERE session_id = '$session_id')";

$result = $conn->query($sql);
$row = $result->fetch_assoc();

?> 

Answer 1

正如我在评论中所说:

"Basically, what you need to do is assign a session array to a post array and then pass that session to other pages (and query in a WHERE clause), then destroy the session on logout."

所以这是您可以使用的逻辑，作为一个基本示例:

旁注:

我很可能需要更多时间来检查您的整个代码来修复它。这更容易/更快。

<?php 

session_start();

$_POST['user'] = "John"; // Take the POST array from your named input

if (!isset($_SESSION['var'])) {

  $_SESSION['var'] = $_POST['user'];
} else {
  echo "It seems the session is already set " . $_SESSION['var'];
}
$username = $_SESSION['var'];

echo $username;

...然后检查后续页面中是否设置了 session 并应用相同的逻辑。

另请注意您的问题下留下的评论。

销毁 session 引用:

• > http://php.net/manual/en/function.session-destroy.php