php - 如何使用单个查询通过 PHP 创建多个 MySQL 表?

标签 php mysql subquery setup-deployment create-table

我正在尝试为我的网站创建一个“设置脚本”。我想创建数据库,同时添加表格和一些内容。到目前为止,这就是我的做法,但使用多个查询似乎有点困惑:

<?php


$servername = "localhost";
$username = "root";
$password = "password";

// Create connection
$conn = new mysqli($servername, $username, $password);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}

// Create database
$sql = "CREATE DATABASE MYDB";
if ($conn->query($sql) === TRUE) {

    echo "1. Database created successfully <br/>";
    $conn->select_db("MYDB");


    $sql_members = "CREATE TABLE MEMBERS (
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    USERNAME VARCHAR(30) NOT NULL,
    EMAIL VARCHAR(40) NOT NULL,
    DISCOUNT VARCHAR(5),
    PASSW CHAR(128),
    ROLE VARCHAR(9)
    )";


    if ($conn->query($sql_members) === TRUE) {
        echo "2. Table MEMBERS created successfully <br/>";
    } else {
        echo "Error creating table: " . $conn->error;
    }

    $sql_content = "CREATE TABLE CONTENT (
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    TITLE VARCHAR(30) NOT NULL,
    TEXT VARCHAR(30) NOT NULL
    )";

    if ($conn->query($sql_content) === TRUE) {
        echo "3. Table CONTENT created successfully <br/>";
    } else {
        echo "Error creating table: " . $conn->error;
    }



} else {
    echo "Error creating database: " . $conn->error;
}

$conn->close();


?>

还有更好的办法吗? 谢谢!

==更新==

我尝试导出数据库并使用生成的 .sql 文件作为我的设置查询,但出现了问题,我得到:

Error creating tables: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'INSERT INTO CONTACTS (ID, NAME, PHONE, EMAIL, ADDRESS, CITY, `COUN' at line 12

CREATE TABLE IF NOT EXISTS `CONTACTS` (
  `ID` int(11) NOT NULL AUTO_INCREMENT,
  `NAME` varchar(25) COLLATE utf8_romanian_ci NOT NULL,
  `PHONE` varchar(16) COLLATE utf8_romanian_ci NOT NULL,
  `EMAIL` varchar(35) COLLATE utf8_romanian_ci NOT NULL,
  `ADDRESS` text COLLATE utf8_romanian_ci NOT NULL,
  `CITY` varchar(16) COLLATE utf8_romanian_ci NOT NULL,
  `COUNTRY` varchar(16) COLLATE utf8_romanian_ci NOT NULL,
  PRIMARY KEY (`ID`)
) ENGINE=InnoDB  DEFAULT CHARSET=utf8 COLLATE=utf8_romanian_ci AUTO_INCREMENT=2 ;

INSERT INTO `CONTACTS` (`ID`, `NAME`, `PHONE`, `EMAIL`, `ADDRESS`, `CITY`, `COUNTRY`) VALUES
(1, 'Peter Brown', '0742062307', '<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="e78881818e8482a7948f8897c984888a" rel="noreferrer noopener nofollow">[email protected]</a>', 'Avenue 13.', 'Santaclaus', 'Austria');

==解决方案==

我需要“multi_query()”来执行多个查询。

最佳答案

你也可以尝试一下:p

$errors = [];

$table1 = "CREATE TABLE MEMBERS (
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    USERNAME VARCHAR(30) NOT NULL,
    EMAIL VARCHAR(40) NOT NULL,
    DISCOUNT VARCHAR(5),
    PASSW CHAR(128),
    ROLE VARCHAR(9)
    )";

$table2 = "CREATE TABLE CONTENT (
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    TITLE VARCHAR(30) NOT NULL,
    TEXT VARCHAR(30) NOT NULL
    )";


$tables = [$table1, $table2];


foreach($tables as $k => $sql){
    $query = @$conn->query($sql);

    if(!$query)
       $errors[] = "Table $k : Creation failed ($conn->error)";
    else
       $errors[] = "Table $k : Creation done";
}


foreach($errors as $msg) {
   echo "$msg <br>";
}

关于php - 如何使用单个查询通过 PHP 创建多个 MySQL 表?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38997569/

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