mysql - 在mysql中从扑克牌中找到两对

Question

您好，我需要帮助来弄清楚如何从扑克牌中找到两对。 我相信我需要计算不同牌的数量，然后根据以下逻辑告诉我它是否是两对:两对是一手扑克牌，包含两张相同等级的牌，两张不同等级的牌和一张不同等级的牌。第三等级；我只是不知道该怎么做。

感谢任何帮助。

这是我的扑克牌 table

+----------+------+------+------+-----------+-----------+
| cardName | face | type | suit | faceValue | gameValue |
+----------+------+------+------+-----------+-----------+
| AC       | no   | A    | C    |         1 |        14 |
| 2C       | no   | 2    | C    |         2 |         2 |
| 3C       | no   | 3    | C    |         3 |         3 |
| 4C       | no   | 4    | C    |         4 |         4 |
| 5C       | no   | 5    | C    |         5 |         5 |
+----------+------+------+------+-----------+-----------+

和扑克牌手

+----------+--------+----+-----+----+----+----+----------+
| playerId | gameId | C1 | C2  | C3 | C4 | C5 | handType |
+----------+--------+----+-----+----+----+----+----------+
|    12789 | 17MET  | QH | QS  | 3D | 3C | 3H |          |
|    12789 | 82SAT  | 7C | 4S  | 4D | 4C | 3H |          |
|    56347 | 03DEC  | 6S | 3S  | 3H | 3C | 3D |          |
|    56347 | 23WSA  | KH | 10H | 7H | 3H | AH |          |
|    56347 | 30DEC  | AC | KH  | KD | 3D | 3S |          |
+----------+--------+----+-----+----+----+----+----------+

我需要获取最后一行

+----------+--------+----+-----+----+----+----+----------+
| playerId | gameId | C1 | C2  | C3 | C4 | C5 | handType |
+----------+--------+----+-----+----+----+----+----------+
|    56347 | 30DEC  | AC | KH  | KD | 3D | 3S |          |
+----------+--------+----+-----+----+----+----+----------+

Answer 1

我会通过 UNION 对每张卡进行预聚合，以获得普通卡，无论花色如何。然后应用分组依据...

select  PlayerID, GameID, left( c1,1 ) as OneCard
   from PlayerHand 
union all 
select  PlayerID, GameID, left( c2,1 ) as OneCard
   from PlayerHand 
union all 
select  PlayerID, GameID, left( c3,1 ) as OneCard
   from PlayerHand 
union all 
select  PlayerID, GameID, left( c4,1 ) as OneCard
   from PlayerHand 
union all 
select  PlayerID, GameID, left( c5,1 ) as OneCard
   from PlayerHand 

这将为您提供一个人/游戏的类似以下内容

playerid  gameid  onecard
12789     17MET   Q
12789     17MET   Q
12789     17MET   3 
12789     17MET   3
12789     17MET   3

现在，您可以轻松查看卡片并可以进行简单的聚合

select
      preQuery.playerid,
      preQuery.gameid,
      preQuery.onecard,
      count(*) as CntThisCard
   from
      ( the entire union query above ) preQuery
   group by
      preQuery.playerid,
      preQuery.gameid,
      preQuery.onecard
   having
      count(*) > 1

根据您的数据，这将返回以下行...

playerid  gameid  onecard  cntThisCard
12789     17MET   Q        2
12789     17MET   3        3  This is a full-house
12789     82SAT   4        3  Three-of-a-kind
56347     03DEC   3        4  Four-of-a-kind
56347     23WSA   (not returned in data set)
56347     30DEC   K        2
56347     30DEC   3        2  Two-pair

现在，如何提取任何“手”，这也会被卷起来......

select
      QryLvl2.PlayerID,
      QryLvl2.GameID
   from
      ( the entire query above returning per-card count ) QryLvl2
   where
      QryLvl2.CntThisCard = 2
   group by
      QryLvl2.PlayerID,
      QryLvl2.GameID
   having
      count(*) = 2

在这种情况下，由于您明确地寻找两对，所以我有 where 子句明确地仅寻找手中有 2 的牌。 count(*) = 2 的组意味着两张不同的牌，这将为您提供最后一手牌。

但正如您从第二张中看到的，您还可以立即识别出 4 同种、葫芦、3 同种、2 对和单高牌中更好的一手牌。

然后，您可以将牌表简化为数字/面，用于确定一对 J/3 比 10 和 9 的手牌更高，因为您不关心牌的花色，只关心它的面值，当与其他手相比。