我有一个像这样的表“schLoc”
------------------------
| id | ... | ... | ... |
------------------------
| 1 | ... | ... | ... |
| 2 | ... | ... | ... |
| 3 | ... | ... | ... |
| 4 | ... | ... | ... |
| 5 | ... | ... | ... |
| .. | ... | ... | ... |
------------------------
还有另一个像这样的“schLocDett”表,其中 schLoc.id=schLocDett.idDoc
-------------------------------
| idDoc | qta | ... | merce |
-------------------------------
| 1 | 1 | ... | fattLoc |
| 1 | 1 | ... | fattSrv |
| 2 | 3 | ... | fattLoc |
| 2 | 2 | ... | notcSrv |
| 2 | 2 | ... | fattSrv |
| 3 | 5 | ... | fattSrv |
| 3 | 3 | ... | notcSrv |
| 3 | 3 | ... | fattLoc |
| 3 | 7 | ... | fattLoc |
| 4 | 5 | ... | notcSrv |
| 4 | 4 | ... | fattSrv |
| 4 | 1 | ... | fattSrv |
| 5 | 1 | ... | notcSrv |
| ... | ... | ... | ....... |
-------------------------------
我想要完整的 schLoc 列表以及每个 id 关联的 qta 总和,但仅限于 Merce=fattLoc。如果不存在,总和将为 0。 这就是我期望的结果
---------------------------
| id | sumQta | ... | ... |
------------------------
| 1 | 1 | ... | ... |
| 2 | 3 | ... | ... |
| 3 | 10 | ... | ... |
| 4 | 0 | ... | ... |
| 5 | 0 | ... | ... |
| .. | ... | ... | ... |
---------------------------
我尝试这样做:
SELECT TOT.sumQta, TAB.*,
FROM schLoc AS TAB, schLocDett AS DETT,
(SELECT idDoc, SUM(qta) AS sumQta
FROM schLocDett
WHERE merce='fattLoc'
GROUP BY idDoc) AS TOT
WHERE TAB.id>0
AND TAB.id=DETT.idDoc
AND TAB.id=TOT.idDoc
但未获取 ID 4 和 5
欢迎任何建议
最佳答案
SELECT TAB.*, COALESCE(TOT.sumQta, 0) AS sumQta
FROM schLoc TAB
LEFT JOIN
(
SELECT idDoc, SUM(qta) AS sumQta
FROM schLocDett
WHERE merce = 'fattLoc'
GROUP BY idDoc
) TOT
ON TAB.id = TOT.idDoc
输出:
此处演示:
Rextester
关于mySQL 从两个连接表中选择子查询中的数据总和,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43249450/