这是我的代码。但我在加载超过 1000 行的结果时遇到一些问题。
如何更改代码以检查首先创建分页的查询结果数。然后,只得到分页页面的结果?
function showResult(req, res){
var n = req.query.query;
mysql_conn.query('SELECT query_text FROM catalogsearch_query WHERE query_text LIKE "%' + n + '%" ORDER BY popularity DESC LIMIT 0 , 10', function (error, rows) {
mysql_crawl.query('SELECT prod_name, full_price, discount_price, quantity, fulltext_id,prod_link, images, prod_desc, status, web_name,web_logo FROM `catalogsearch_fulltext` WHERE MATCH(data_index) AGAINST("'+n+'") ', function(error, product_data) {
var totalItems = product_data.length, itemts=product_data;
//set default variables
var totalResult = totalItems,
pageSize = 10,
pageCount = Math.floor(totalResult / pageSize)
currentPage = 1
//set current page if specifed as get variable (eg: /?page=2)
if (typeof req.query.page !== 'undefined') {
currentPage = +req.query.page;
}
//render index.ejs view file
res.render('result.html', {result: n,
related: rows.map(row => row.query_text),
page_num: p,
product_data: product_data,
totalItems: totalItems,
pageSize: pageSize,
pageCount: pageCount,
currentPage: currentPage})
});
});
}
最佳答案
首先获得结果的总行数
从表中选择 COUNT(*),其中 1 = 1;
第二个是获取行结果但受 ex 限制的查询。 10 偏移量首先从零开始
SELECT * FROM 表 WHERE 1 = 1 LIMIT 10, 0;
这意味着结果将从 0 开始,然后对于下一页,您应该添加 10 作为偏移量
SELECT * FROM 表 WHERE 1 = 1 LIMIT 10, 10;
所以它从 10 开始到 20
关于javascript - 优化结果页优先查询结果条数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43889816/