mysql - 如何使用 laravel 查询获取具有相似兴趣的用户

Question

我有这个 sql 查询来获取至少有 3 个共同兴趣的用户。

$get_similar =  $db->query(sprintf('SELECT ui.user_id, COUNT( * ) AS common_interests
                                                FROM users_interests ui
                                                WHERE ui.interests_id
                                                IN (

                                                SELECT ui2.interests_id
                                                FROM users_interests ui2
                                                WHERE ui2.user_id = %s
                                                )
                                                AND ui.user_id <> %s
                                                GROUP BY ui.user_id
                                                HAVING common_interests >2
                                                ', secure($this->_data['user_id']), secure($this->_data['user_id']) ));

如何将上面的sql查询转换为laravel eloquent查询？

Answer 1

以下查询即可解决问题

$user_interests = User::find($user_id)->interests->pluck('id')->toArray();

    $get_similar = DB::table('users_interests')
        ->select(DB::raw('count(*) as common_interests, user_id'))
        ->whereIn('interest_id', $user_interests)
        ->where('user_id','<>', 3)
        ->groupBy('user_id')
        ->havingRaw('COUNT(*) > 2')
        ->get();