php - 从子查询进行查询

Question

我正在尝试将以下 sql 查询传递给 Doctrine:

SELECT id, name, count(*) FROM (SELECT r.id, r.name, f.timestamp FROM `food_log` as f inner join recipe as r on f.recipe_id = r.id WHERE f.user_id = 6 and timestamp > "2016-09-01" and recipe_id is not null group by f.timestamp, r.id) a GROUP BY a.id ORDER BY count(*) DESC

它应该返回给我食谱，其中包含特定用户使用选定时间戳中的单个食谱的次数。

现在我正在尝试使用 Doctrine 1.2 和 Symfony 1.4 执行此操作，但是我不知道如何从子查询进行查询，我正在尝试执行类似的操作

        $subQuery = Doctrine_Query::create()
        ->select('r.id, r.name, f.timestamp')
        ->from('FoodLog f')
        ->innerJoin('f.Recipe r')
        ->where('f.user_id = ?', $userId)
        ->andWhere('timestamp > ?', "2016-09-01")
        ->andWhere('f.recipe_id is not null')
        ->andWhere('r.is_premium = ?', $premium)
        ->groupBy('f.timestamp, r.id')
        ->getSqlQuery();

    $query = Doctrine_Query::create()
    ->select('id, name, count(*)')
    ->from($subQuery)
    ->groupBy('id')
    ->orderBy('count(*) DESC');

    return $query->fetchArray();

有人知道我哪里错了吗？ 非常感谢您的回复!

Answer 1

基本上，您无法在此版本的 Doctrine 中执行嵌套查询。我建议通过学说连接器使用原始 SQL 查询:

$sql = 'SELECT id, name, count(*) FROM (SELECT r.id, r.name, f.timestamp FROM `food_log` as f inner join recipe as r on f.recipe_id = r.id WHERE f.user_id = 6 and timestamp > "2016-09-01" and recipe_id is not null group by f.timestamp, r.id) a GROUP BY a.id ORDER BY count(*) 
DESC';
$conn = Doctrine_Manager::getInstance()->getCurrentConnection();
$result = $conn->execute($sql);

foreach($result as $data){
    // do something
}

由于您没有对物体进行水合处理，因此您应该会发现这种方法效果很好。