MySQL:按多列分组未给出准确的结果

Question

我有一个包含 5 列的表，即:

before_1, before_2, before_3, rule, name

其中 before_1、before_2 和 before_3 是文档中名称/单词之前的三个单词。

我想找到的是:

Which are the two words that occur together before a name. I don't want just the top words, but all the words sorted by the number of occurrences.

我尝试了以下几个查询，但这对我不起作用。

select count(before_2),count(before_3),name from data_with_before_words group by name;

两列的计数相同，这不是我所期望的。

示例数据:

前 5 行:

before_1,before_2,before_2,rule,name

a,league,of,Persona,Amell
the,assasin,of,Persona,Amell
the,league,of,Persona,Amell
a,assasin,of,Persona,Amell
a,league,of,Persona,Amell

预期输出:

league,of,3,Amell
assasin,of,2,Amell

如有任何帮助，我们将不胜感激。

Answer 1

要获得预期的输出，您可以使用以下查询

select before_2,before_3,name,count(*)
from data_with_before_words 
group by before_2,before_3,name
order by count(*) desc

Demo