MySQL根据文本单词进行计数

Question

因为我正在计算有多少个 SKU(基于每个 SKU)，据我所知，SKU“H-ROOT-C”有 3 件商品已退款。

SELECT 
    sku,
    count(IF(transaction_type = 'Refund'AND amount_description = 'Principal' AND amount_type = 'ItemPrice', sku, 0)) AS 'refund_QTY_Order'
FROM
    settlements_qty_test
WHERE
    (sku NOT LIKE '%loc%'
        AND sku NOT LIKE 'isc%'
        AND sku NOT LIKE 'trek%')
GROUP BY SKU ='H-ROOT-C'
HAVING sku IS NOT NULL AND LENGTH(sku) > 0
ORDER BY refund_QTY_Order ASC

结果输出

'H-ROOT-C', '125'

我一直得到结果，因为所有退款计数为 125，因为我希望此搜索重点关注每组 SKU，而 h-root-C 应该是 3 件商品返回，而不是 125 件商品返回。我不需要所有 SKU 退款，我只想要这个 SKU='H-root-c'。

Answer 1

您可以将其简化为:

SELECT sku
       sum( (transaction_type = 'Refund' AND
             amount_description = 'Principal' AND
             amount_type = 'ItemPrice'
            )
           ) AS refund_QTY_Order
FROM settlements_qty_test
WHERE sku NOT LIKE '%loc%' AND
      sku NOT LIKE 'isc%' AND
      sku NOT LIKE 'trek%' AND
      LENGTH(sku) > 0
GROUP BY SKU
ORDER BY refund_QTY_Order ASC;

与NULL的比较是多余的。我将条件逻辑留在了 SELECT 中，因此您将获得 0 值。