mysql - 大小写计数未给出正确结果

Question

我正在使用查询来生成计数。以下是我的查询

SELECT COUNT(DISTINCT sur.`customer_id`) AS 'Survey Done'
 ,COUNT(CASE WHEN sn.operator_name LIKE '%Zong%' AND sn.`signal_strength` = 'No Signal' THEN 1 ELSE NULL END) AS 'Zong No Signal'
 ,COUNT(CASE WHEN sn.operator_name LIKE '%Mobilink%' AND sn.`signal_strength` = 'No Signal' THEN 1 ELSE NULL END) AS 'Mobilink No Signal'
 ,COUNT(CASE WHEN sn.operator_name LIKE '%Ufone%' AND sn.`signal_strength` = 'No Signal' THEN 1 ELSE NULL END) AS 'Ufone No Signal'
 ,COUNT(CASE WHEN sn.operator_name LIKE '%Telenor%' AND sn.`signal_strength` = 'No Signal' THEN 1 ELSE NULL END) AS 'Telenor No Signal'
 ,COUNT(CASE WHEN sur.`pole_type` LIKE '%Wall%' THEN 1 ELSE NULL END) AS 'Wall'
 ,COUNT(CASE WHEN sur.`pole_type` LIKE '%PC Pole%' THEN 1 ELSE NULL END) AS 'PC Pole'
 ,COUNT(CASE WHEN sur.`pole_type` LIKE '%Structure Pole%' THEN 1 ELSE NULL END) AS 'Structure pole'
 ,COUNT(CASE WHEN sur.`pole_type` LIKE '%Spon pole%' THEN 1 ELSE NULL END) AS 'Spon pole'
 ,sd.`sub_div_code` AS 'SD Code',  
 sd.`name` AS 'SD Name', 
 sd.`circle_name` AS 'Circle Name', 
 sd.`division_name` AS 'Division Name'
 FROM `survey` sur 
 INNER JOIN `survey_hesco_subdivision` sd ON sur.`sub_division` = 
 sd.`sub_div_code`
 INNER JOIN `survey_networks` sn ON sur.`id` = sn.`survey_id`
 WHERE sur.`customer_id` IN ('37010185878',
'37010718785',
'37010718759',
'37010357911',
'37010673539',
'37010673796',
'37010672166',
'37010672162')
 GROUP BY sd.`name`

所有计数都是正确的，但以下部分的值不正确

,COUNT(CASE WHEN sur.`pole_type` LIKE '%Wall%' THEN 1 ELSE NULL END) AS 'Wall'
,COUNT(CASE WHEN sur.`pole_type` LIKE '%PC Pole%' THEN 1 ELSE NULL END) AS 'PC Pole'
,COUNT(CASE WHEN sur.`pole_type` LIKE '%Structure Pole%' THEN 1 ELSE NULL END) AS 'Structure pole'
,COUNT(CASE WHEN sur.`pole_type` LIKE '%Spon pole%' THEN 1 ELSE NULL END) AS 'Spon pole'

它们的输出是10、4、24和0。但实际计数是 4、1、7 和 0

示例输出为

对于某些记录，但并非全部记录，最后一个值spon rod是0，因此它的计数也不正确。

如何获得这些值的正确计数？我还尝试过使用 = 符号替换 LIKE 但仍然无法给出正确的结果。我也看过这个solution

任何帮助将不胜感激

Answer 1

您可以使用 SUM 而不是 Count 和 ELSE 设置 0

SELECT COUNT(DISTINCT sur.`customer_id`) AS 'Survey Done'
,SUM(CASE WHEN sur.`pole_type` LIKE '%Wall%' THEN 1 ELSE 0 END) AS 'Wall'
,SUM(CASE WHEN sur.`pole_type` LIKE '%PC Pole%' THEN 1 ELSE 0 END) AS 'PC Pole'
,SUM(CASE WHEN sur.`pole_type` LIKE '%Structure Pole%' THEN 1 ELSE 0 END) AS 'Structure pole'
,SUM(CASE WHEN sur.`pole_type` LIKE '%Spon pole%' THEN 1 ELSE 0 END) AS 'Spon pole'
,sur.`sub_division`
FROM `survey` sur 

如果你想区分sur.sub_division只需添加group by by sur.sub_division

SELECT COUNT(DISTINCT sur.`customer_id`) AS 'Survey Done'
,SUM(CASE WHEN sur.`pole_type` LIKE '%Wall%' THEN 1 ELSE 0 END) AS 'Wall'
,SUM(CASE WHEN sur.`pole_type` LIKE '%PC Pole%' THEN 1 ELSE 0 END) AS 'PC Pole'
,SUM(CASE WHEN sur.`pole_type` LIKE '%Structure Pole%' THEN 1 ELSE 0 END) AS 'Structure pole'
,SUM(CASE WHEN sur.`pole_type` LIKE '%Spon pole%' THEN 1 ELSE 0 END) AS 'Spon pole'
,sur.`sub_division`
FROM `survey` sur 
GROUP BY sur.`sub_division`

编辑

我猜问题出在Group byfiled上，你可以试试这个。

SELECT COUNT(DISTINCT sur.`customer_id`) AS 'Survey Done'
     ,SUM(CASE WHEN sn.operator_name LIKE '%Zong%' AND sn.`signal_strength` = 'No Signal' THEN 1 ELSE 0 END) AS 'Zong No Signal'
     ,SUM(CASE WHEN sn.operator_name LIKE '%Mobilink%' AND sn.`signal_strength` = 'No Signal' THEN 1 ELSE 0 END) AS 'Mobilink No Signal'
     ,SUM(CASE WHEN sn.operator_name LIKE '%Ufone%' AND sn.`signal_strength` = 'No Signal' THEN 1 ELSE 0 END) AS 'Ufone No Signal'
     ,SUM(CASE WHEN sn.operator_name LIKE '%Telenor%' AND sn.`signal_strength` = 'No Signal' THEN 1 ELSE 0 END) AS 'Telenor No Signal'
     ,SUM(CASE WHEN sur.`pole_type` LIKE '%Wall%' THEN 1 ELSE 0 END) AS 'Wall'
     ,SUM(CASE WHEN sur.`pole_type` LIKE '%PC Pole%' THEN 1 ELSE 0 END) AS 'PC Pole'
     ,SUM(CASE WHEN sur.`pole_type` LIKE '%Structure Pole%' THEN 1 ELSE 0 END) AS 'Structure pole'
     ,SUM(CASE WHEN sur.`pole_type` LIKE '%Spon pole%' THEN 1 ELSE 0 END) AS 'Spon pole'
     ,sd.`sub_div_code` AS 'SD Code',  
     sd.`name` AS 'SD Name', 
     sd.`circle_name` AS 'Circle Name', 
     sd.`division_name` AS 'Division Name'
 FROM `survey` sur 
 INNER JOIN `survey_hesco_subdivision` sd ON sur.`sub_division` = 
 sd.`sub_div_code`
 INNER JOIN `survey_networks` sn ON sur.`id` = sn.`survey_id`
 WHERE sur.`customer_id` IN 
 ('37010185878',
'37010718785',
'37010718759',
'37010357911',
'37010673539',
'37010673796',
'37010672166',
'37010672162')
 GROUP BY 
     sd.`sub_div_code`, 
     sd.`name`,
     sd.`circle_name`, 
     sd.`division_name`

SQLFiddle