这里我有 3 个表,使用我必须计数
trip_details
id allocationId tripId
1 7637 aIz2o
2 7626 osseC
3 7536 01LEC
4 7536 78w2w
5 7640 S60zF
6 7548 ruaoR
7 7548 Qse6s
escort_allocation
id allocationId escortId
3 7637 1
4 7626 1
5 7627 1
6 7536 1
7 7640 1
7 7548 1
cab_allocation
allocationId allocationType
7637 Daily Trip
7626 Daily Trip
7627 Daily Trip
7536 Adhoc Trip
7640 Adhoc Trip
7548 Daily Trip
使用上表我必须得到计数,我尝试过,但没有达到我的预期结果。
我尝试了sql查询
SELECT a.`tripId`
FROM `trip_details` a
INNER JOIN escort_allocation b ON a.`allocationId` = b.`allocationId`
GROUP BY a.`allocationId`
LIMIT 0 , 30
我就是这样
tripId
01LEC
ruaoR
osseC
aIz2o
S60zF
我总共得到了 6 个 tripId
,所以现在我想进行计数,所以我使用这个查询
SELECT COUNT(*)
FROM `trip_details` a
INNER JOIN escort_allocation b ON a.`allocationId` = b.`allocationId`
GROUP BY a.`allocationId`
LIMIT 0 , 30
但是这个查询不起作用。我得到如下结果
2
2
1
1
1
MY MYSQL TABLES AND VALUES LOOK LIKE THIS
CREATE TABLE `trip_details` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`allocationId` int(11) NOT NULL,
`tripId` varchar(100) NOT NULL,
PRIMARY KEY (`id`),
KEY `tripId` (`tripId`),
KEY `allocationId` (`allocationId`)
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=latin1 ;
INSERT INTO trip_details
(id, allocationId, tripId)
VALUES
(1, 7637, '00SwM'),
(2, 7626, '00SwM'),
(3, 7536, '00SwM'),
(4, 7536, '01hEU'),
(5, 7640, '01hEU'),
(6, 7548, 'IRZMS'),
(7, 7548, 'IRZMS');
CREATE TABLE `escort_allocation` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`allocationId` int(11) NOT NULL,
`escortId` varchar(100) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=latin1 ;
INSERT INTO escort_allocation
(id, allocationId, escortId)
VALUES
(1, 7637, 'ssda'),
(2, 7626, 'adad'),
(3, 7627, 'sfsaf'),
(4, 7536, 'ssaf'),
(5, 7640, 'asf'),
(6, 7548, 'a3r');
CREATE TABLE `cab_allocation` (
`allocationId` int(11) NOT NULL AUTO_INCREMENT,
`allocationType` enum('Daily Trip','Adhoc Trip') NOT NULL,
PRIMARY KEY (`allocationId`)
) ENGINE=InnoDB AUTO_INCREMENT=7695 DEFAULT CHARSET=latin1;
INSERT INTO cab_allocation
(allocationId, allocationType)
VALUES
(7637, 'Daily Trip'),
(7626, 'Daily Trip'),
(7627, 'Daily Trip'),
(7536, 'Adhoc Trip'),
(7640, 'Adhoc Trip'),
(7548, 'Daily Trip');
最佳答案
你可以试试这个
SELECT COUNT(DISTINCT (a.`tripId`))
FROM `trip_details` a
INNER JOIN escort_allocation b ON a.`allocationId`=b.`allocationId`
LIMIT 0 , 30
由于GROUP BY
,所有allocationId都有单独的计数。
关于mysql - mysql中如何使用group by和count,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49406709/