我想获取总金额最大的用户的user_id
和总金额。我无法使用 LIMIT
,因为这只会返回 1 条记录(多个用户的总金额可能相同)
这是我的数据架构和一些记录
CREATE TABLE transactions (
id BIGINT(20) NOT NULL AUTO_INCREMENT,
user_id BIGINT(20) NOT NULL,
amount FLOAT NOT NULL, PRIMARY KEY (id)
);
INSERT INTO transactions (user_id, amount) VALUES
(1, 1000),
(1, 1000),
(1, 1000),
(2, 2000),
(2, 1000),
(3, 1000);
这是预期的结果。
+---------+------+
| user_id | sum |
+---------+------+
| 1 | 3000 |
| 2 | 3000 |
+---------+------+
我可以使用下面的sql得到上面的结果。但是,我不知道是否有更好的方法。是否有必要重复同一个子查询两次?谢谢。
SELECT T1.user_id, T1.sum
FROM (
SELECT user_id, SUM(amount) as sum
FROM transactions
GROUP BY user_id
) T1
WHERE T1.sum = (
SELECT MAX(T2.sum)
FROM (
SELECT user_id, SUM(amount) as sum
FROM transactions
GROUP BY user_id
) T2
)
GROUP BY T1.user_id;
最佳答案
那么您可以将查询简化为
SELECT user_id, SUM(amount) as sum
FROM transactions
GROUP BY user_id
HAVING SUM(amount) = (
SELECT SUM(amount) as sum
FROM transactions
GROUP BY user_id
ORDER BY SUM(amount) DESC
LIMIT 1
)
关于MySQL - 查找分组总和的最大值(无限制),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49838518/