我正在使用 Hibernate 从数据库获取 JSON 对象。我希望 JSON 对象应包含最近创建的 VGI 中唯一前两个的所有详细信息。但我不知道如何在不使用 HQL 查询时限制结果集,然后根据创建日期进行排序。它正在从 MySQL 数据库获取所有详细信息。
import java.util.Date;
import java.util.List;
import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.ManyToOne;
import javax.persistence.OneToMany;
import javax.persistence.OneToOne;
import javax.persistence.Table;
@Entity
@Table(name = "vgi", catalog = "coworkee5")
public class VGI {
@ManyToOne
@JoinColumn(name = "employee_id", referencedColumnName = "id", insertable = false, updatable = false)
private Employees employees;
public Employees getEmployees() {
return employees;
}
public void setEmployees(Employees employees) {
this.employees = employees;
}
@OneToMany(cascade = CascadeType.ALL, targetEntity = VgiGoals.class, mappedBy = "vgi")
private List<VgiGoals> vgiGoals;
public List<VgiGoals> getVgiGoals() {
return vgiGoals;
}
public void setVgi_goals(List<VgiGoals> vgiGoals) {
this.vgiGoals = vgiGoals;
}
public VGI() {
}
@Id
@Column(name = "id")
private String id;
@Column(name = "title")
private String vgi;
@Column(name = "employee_id")
private String employee_id;
@Column(name = "created_on")
private String created;
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public String getvgi() {
return vgi;
}
public void setvgi(String vgi) {
this.vgi = vgi;
}
public String getEmployee_id() {
return employee_id;
}
public void setEmployee_id(String employee_id) {
this.employee_id = employee_id;
}
public String getCreated() {
return created;
}
public void setCreated(String created) {
this.created = created;
}
}
最佳答案
添加@OrderBy
注释进行排序,如下所示。
@OneToMany(cascade = CascadeType.ALL, targetEntity = VgiGoals.class, mappedBy = "vgi")
@OrderBy("createdOn DESC")
private List<VgiGoals> vgiGoals;
注意:将 createOn 替换为 VgiGoals 类中的日期字段。
为了限制在查询中使用以下方法。
query.setFirstResult(1).setMaxResults(10);
关于java - 我们如何在 Hibernate 中按日期对结果进行排序?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53442339/