我的数据如下所示:
ID post_author post_title guid 3309 21 Should somebody not yet on SQL 2008 wait for SQL 2008 R2, since it's near release? http://sql.stackexchange.com/questions/379/should-somebody-not-yet-on-sql-2008-wait-for-sql-2008-r2-since-its-near-release 1695 429 How do we politely decline well meaning advice from the Grandmother? http://moms4mom.stackexchange.com/questions/1208/how-do-we-politely-decline-well-meaning-advice-from-the-grandmother 556 173 Books on how to be a great dad http://moms4mom.stackexchange.com/questions/1042/books-on-how-to-be-a-great-dad 160 30 Building an ice hockey net cam http://photo.stackexchange.com/questions/8/building-an-ice-hockey-net-cam 159 30 Generic commercial photo release form http://photo.stackexchange.com/questions/4/generic-commercial-photo-release-form
我需要创建一个查询，对 GUID 字段(根 URL)的一部分数据进行分组，并对每个字段的 POST_AUTHOR 进行计数。
我正在寻找的结果是这样的:
Site Count of Authors http://sql.stackexchange.com 1 http://moms4mom.stackexchange.com 2 http://photo.stackexchange.com 2
如果有人帮助我构建 SQL，我将不胜感激。
最佳答案
SELECT COUNT(POST_AUTHOR) AS AUTHOR_COUNT, GUID FROM TABLE_NAME GROUP BY GUID
关于sql - 如何使用 MySQL 进行分组和计数，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/1589834/