每次打开下面的代码时，我的页面都会停止加载...它看起来正确，表格和字段也正确。
<select name="common" style="width: 136px;">
<?php
$group1 = mysql_fetch_array(mysql_query("SELECT country FROM lang_list WHERE grouping = '1' ORDER BY p_order"));
while($row = $group1){
echo "<option value=\"$group1\">$group1</option>\n";
}
?>
</select>
最佳答案
<?php
$group1 = mysql_query("SELECT country FROM lang_list WHERE grouping = '1' ORDER BY p_order");
while($row = mysql_fetch_array($group1)){
echo "<option value=\"$row[country]\">$row[country]</option>\n";
}
?>
关于php - mysql_fetch_array问题代码未处理，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/3931854/